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son4ous [18]
3 years ago
5

Express the following 48-bit binary MAC address in hexadecimal 11101100 – 00100111 – 10111001 – 11010101 – 01101111 – 10100011

Mathematics
2 answers:
Zanzabum3 years ago
6 0

Answer:

EC - 27 - B9 - D5 - 6F - A3

Step-by-step explanation:

Formula : (11101100)2 = (EC)16 = ECh

Sergio [31]3 years ago
6 0

Answer:

EC - 27 - B9 - D5 - 6F - A3.

Step-by-step explanation:

 11101100       Break these up in sets of 4 from the right:

= 1110 1100    Now convert each 4 digit part to hexadecimal:

= E      C

= EC

00100111    In a similar way this is:

27

10111001 = B9

11010101 =  D5

01101111 = 6F

10100011 = A3.

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slope = rise/run = 2/1 = 2

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Rewrite the system of linear equations as a matrix equation AX = B.
iren2701 [21]

Answer:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

Step-by-step explanation:

Let's find the answer.

Because we have 3 equations and 3 variables (x1, x2, x3) a 3x3 matrix (A) can be constructed by using their respectively coefficients.

Equations:

Eq. 1 : x1 + 2x2 + 5x3 = 5

Eq. 2 : x1 + x2 + x3 = 6

E1. 3 : 4x1 + 6x2 + 5x3 = 7

Coefficients for x1 ; x2 ; x3

From eq. 1 : 1 ; 2 ; 5

From eq. 2 : 1 ; 1 ; 1

From eq. 3 : 4 ; 6 ; 5

So matrix A is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]

And the vector of vriables (X) is:

\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]

Now we can find the resulting vector (B) using the 'resulting values' from each equation:

\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

In conclusion, AX=B is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

7 0
3 years ago
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Nataly [62]

Answer:

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Step-by-step explanation:

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  2. you would flip the 2/1 to 1/2, and make the divide sign into a multiplication sign.
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7 0
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