Answer:
33
Step-by-step explanation:
6x - 3y
=> x = 5, y = -1 Substitute in the above equation,
=> 6(5) - 3(-1)
=> 6(5) + 3
=> 30 + 3
=> 33
Answer: 
Step-by-step explanation:
Given
For figure (i) both triangles are congruent


For figure (ii)
Two triangles WXZ and WZY are congruent

Answer:
2
Step-by-step explanation:
We are asked to perform the subtraction
x² + xy - 3y² - (5x² - xy + y²) ← distribute the parenthesis by - 1
= x² + xy - 3y² - 5x² + xy - y² ← collect like terms
= (x² - 5x²) + (xy + xy) + (- 3y² - y² )
= - 4x² + 2xy - 4y²
Answer:
68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds
This is the pvalue of Z when X = 8.6 subtracted by the pvalue of Z when X = 6.4. So
X = 8.6



has a pvalue of 0.8413
X = 6.4



has a pvalue of 0.1587
0.8413 - 0.1587 = 0.6826
68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds