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Daniel [21]
3 years ago
7

The expression (7+8x)+2x is simplified in several steps below. For each step, choose the reason that best justifies it. No links

please

Mathematics
1 answer:
igomit [66]3 years ago
7 0

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The greatest common factor of −27x2yz5 + 15x3z3
Goryan [66]
We have that
−27x2yz5 + 15x3z3

we know that
27-------------> 3³
15-------------> 3*5
z^5-----------> z² * z³
x³------------> x² * x

substituting in the original expression<span>

−27x2yz5 + 15x3z3---------->[-3</span>³*x²*y*z³*z²]+[3*5*x²*x*z³]

[-3³*x²*y*z³*z²]+[3*5*x²*x*z³]-------> [3*x² *z³]*{[-3² *y*z²]+[5*x]}

the greatest common factor is [3*x² *z³]
8 0
3 years ago
Solve for x <br><br> 2x^2 - 8x + 5 = 0<br><br> x= ____ or x= ______
lisov135 [29]
\left[x _{2}\right] = \left[ 2+\frac{\sqrt{6}}{2}\right][x​2​​]=[2+​2​​√​6​​​​​] this is answer
7 0
4 years ago
Read 2 more answers
Is the graph increasing, decreasing, or constant?
djyliett [7]

Answer:

It is increasing.

Step-by-step explanation:

Given the graph of a straight line, there are several ways to find its equation.

Method 1: This method works only if the y intercept is visible.

Find any two points, (x1, y1) and (x2, y2), on the line and substitute their coordinates into the following formula to get m:

Get b from inspection of the y intercept of the graph.

Substitute the numbers that you have obtained for m and b into the equation y = m x + b.

Method 2: This method works even if the y intercept is not visible.

As in method 1, find any two points, (x1, y1) and (x2, y2), on the line and substitute their coordinates into the following formula to get m:

Substitute the number that you obtained for m into the equation y = m x + b. Also, take one of the points, say (x1, y1), and substitute its coordinates into the equation. This gives:

y1 = m x1 + b

It may not look like it, but this equation has only one variable, b, and you can easily solve for it.

Substitute the numbers that you have obtained for m and b into the equation y = m x + b.

Method 3: This method has the advantage that it uses only algebra, not geometry, and can be applied to any type of function, not just the straight line:

Find two points, (x1, y1) and (x2, y2), that are on the line. Take the first point, (x1, y1), and substitute it into the straight line equation, y = m x + b. This gives:

y1 = m x1 + b

Similarly, take the second point, (x2, y2), and substitute it into the straight line equation, y = m x + b. This gives:

y2 = m x2 + b

Together, these two equations constitute a system of two equations in the two unknowns, m and b. We can solve them for m and b using the elimination method. To be specific, if we subtract the first equation from the second, then b is eliminated and we get the equation:

y2 − y1 = m x2 − m x1,

which, when solved for m, gives the same equation as in the other two methods, namely:

Find b by back-substitution. To be specific, substitute the number that you obtained for m into one equation of the system of equations, say into y1 = m x1 + b. It may not look like it, but this equation has only one variable, b, and you can easily solve for it

7 0
3 years ago
Can somebody help me please!!!
Effectus [21]

Answer:

Part A: 0

Part B: 0 or 1

Step-by-step explanation:

Part A: anything to the 0 power is 1 (x^0= x^y-y) if you solve 7^2 you get 49. 49^0= 1

Part B: Because it is already being raised to the power of 0, if x=0 it will remain equal to one (as explained above). Anything raised to the 1 power is itself, so 7^0= 1 and 1^1 =1

Hope this helped!

3 0
4 years ago
Rationalize the denominator. write it in simplest terms<br><br>    3<br>------<br>√12x
Softa [21]
The idea being, you multiply top and bottom by a value that will raise the radicand in the denominator, to the same as the root, thus coming out of the root, so, let's do so

\bf \cfrac{3}{\sqrt{12x}}\cdot \cfrac{\sqrt{12x}}{\sqrt{12x}}\implies \cfrac{3\sqrt{12x}}{\sqrt{(12x)^2}}\implies \cfrac{3\sqrt{12x}}{12x}\implies \cfrac{\sqrt{12x}}{4x}
4 0
4 years ago
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