X + 2x + x + 10 = 90
4x = 80
x = 20
Hi
Left to do 40% of the shopping
12 items ⇒ 60% of the items
x items ⇒ 40% of the items
60x = 12(40)
60x = 480
x = 480/60
x = 48/6
x = 8 items
Answer:
Left 8 items of the list (40% of the shopping)
Items: 12+8 = 20 items on her list
<u>Answer</u><u>:
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Required integer is -12.
Step-by-step explanation:
Given:
Required number is integer.
Required integer is less than zero
greater than -13.
When number is substracted from -11, result is positive.
To Find:
The integer=?
Solution:
Lets assume required integer = x
As Required integer is less than zero and greater than -13 ,
-13 < x < 0 ------(1)
Also when number is subtracted from -11, result is positive.
=> -11 – x > 0
=> -11 > x -------(2)
So form 1 and 2
-13 < x < -11 that is x is an integer which is less than -11 and greater than -13. There is only one integer between -13 and -11 that is -12.
Hence required integer is -12.
Answer:
49/8 is the value of k
Step-by-step explanation:
We have the system
x = -2y^2 - 3y + 5
x=k
We want to find k such that the system intersects once.
If we substitute the second into the first giving us k=-2y^2-3y+5 we should see we have a quadratic equation in terms of variable y.
This equation has one solution when it's discriminant is 0.
Let's first rewrite the equation in standard form.
Subtracting k on both sides gives
0=-2y^2-3y+5-k
The discriminant can be found by evaluating
b^2-4ac.
Upon comparing 0=-2y^2-3y+5-k to 0=ax^2+bx+c, we see that
a=-2, b=-3, and c=5-k.
So we want to solve the following equation for k:
(-3)^2-4(-2)(5-k)=0
9+8(5-k)=0
Distribute:
9+40-8k=0
49-8k=0
Add 8k on both sides:
49=8k
Divide both sides by 8"
49/8=k
Answer:
x=72.6
Step-by-step explanation:
use inverse trig because your finding a missing angle. use tan because you haved opp/adj
tan-1=(16/5)
x=tan-1(16/5)
*use a calculator
x=72.6
