Answer:
TM = (3,-9,-9)
The magnitude of TM = 3√19
Step-by-step explanation:
Given T=(-5,8,3) and M = (-2,-1,-6)
TM is the difference between the vector M and the vector T
So,
TM = M - T = (-2,-1,-6) - (-5,8,3) = (-2+5 , -1-8 , -6-3) = (3,-9,-9)
The magnitude of TM = The distance of TM =
<u>So, TM = (3,-9,-9) and |TM| = 3√19</u>
4 years old is the answer i think
THIS IS THE COMPLETE QUESTION BELOW
The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.
Answer
$168.27
Step by step Explanation
Given p=90000/400+3x
With the limits of 40 to 50
Then we need the integral in the form below to find the average price
1/(g-d)∫ⁿₐf(x)dx
Where n= 40 and a= 50, then if we substitute p and the limits then we integrate
1/(50-40)∫⁵⁰₄₀(90000/400+3x)
1/10∫⁵⁰₄₀(90000/400+3x)
If we perform some factorization we have
90000/(10)(3)∫3dx/(400+3x)
3000[ln400+3x]₄₀⁵⁰
Then let substitute the upper and lower limits we have
3000[ln400+3(50)]-ln[400+3(40]
30000[ln550-ln520]
3000[6.3099×6.254]
3000[0.056]
=168.27
the average price p on the interval 40 ≤ x ≤ 50 is
=$168.27
The answer is 5/6 I think
9514 1404 393
Answer:
BC ≈ 9.6 mi
Step-by-step explanation:
The mnemonic SOH CAH TOA reminds you of the relationships between sides and angles in a right triangle.
Tan = Opposite/Adjacent
tan(58°) = BC/(6 mi)
BC = (6 mi)tan(58°)
BC ≈ 9.6 mi