Question

Can you please put steps swell

Answer 1

Step-by-step explanation:

If the vector CD is a multiple of the vector BC

(CD = kBC, where k is a real constant

and k =/= 0),

Then BCD is a straight line.

Vector BC = Vector BA - Vector CA

= (5a - 2b) - (3a + b) = (2a - 3b).

Vector CD = Vector CA + Vector AD

= (3a + b) + (3a - 10b) = (6a - 9b)

Since 3(2a - 3b) = (6a - 9b), => k = 3,

The points B, C and D are collinear.

Hence we conclude BCD is a straight line.