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Volgvan
3 years ago
5

What value does each equation need to be multiplied by in order to eliminate the x terms equation 1 6x-5y=-4 equation 2 4x+2y=28

Mathematics
2 answers:
ivann1987 [24]3 years ago
6 0
Equation1= -2/3 +5/6y
equation2= 7-1/2y
spayn [35]3 years ago
5 0
You need to find what x is equal to for each equation, so you can sub why x is equal to in the place I'd x to eliminate the variable
1. 6x-5y=-4
6x=5y-4
X=5/6y-2/3
2. 4x+2y=28
4x=-2y+28
X=-1/2y+7
Hope this helps!
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The equivalent is the expressions that are in different forms but are equal to the same value.

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marin [14]

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\begin{bmatrix}\mathrm{Solution:}\:&\:x\le \frac{1200}{499}\:\\ \:\mathrm{Decimal:}&\:x\le \:2.40480\dots \\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:\frac{1200}{499}]\end{bmatrix}

Step-by-step explanation:

20\ge \:8+4.99x\\Switch\:sides\\8+4.99x\le \:20\\\mathrm{Multiply\:both\:sides\:by\:}100\\8\cdot \:100+4.99x\cdot \:100\le \:20\cdot \:100\\Refine\\800+499x\le \:2000\\\mathrm{Subtract\:}800\mathrm{\:from\:both\:sides}\\800+499x-800\le \:2000-800\\Simplify\\499x\le \:1200\\\mathrm{Divide\:both\:sides\:by\:}499\\\frac{499x}{499}\le \frac{1200}{499}\\Simplify\geq \\x\le \frac{1200}{499}

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3 years ago
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