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Volgvan
3 years ago
5

What value does each equation need to be multiplied by in order to eliminate the x terms equation 1 6x-5y=-4 equation 2 4x+2y=28

Mathematics
2 answers:
ivann1987 [24]3 years ago
6 0
Equation1= -2/3 +5/6y
equation2= 7-1/2y
spayn [35]3 years ago
5 0
You need to find what x is equal to for each equation, so you can sub why x is equal to in the place I'd x to eliminate the variable
1. 6x-5y=-4
6x=5y-4
X=5/6y-2/3
2. 4x+2y=28
4x=-2y+28
X=-1/2y+7
Hope this helps!
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Solve x + 9 = 18 - 2x
bezimeni [28]
Add 2x to both sides,
3x+9=18
Subtract 9 from both sides. 3x=9
Divide both sides by 3. 
x=3
6 0
2 years ago
Solve the equation by factoring.<br> 3z2 + 3z – 6 = 0<br> z = 3 or z = 2
lana66690 [7]

Answer:

<u>3</u><u>z</u><u>^2 + 3z - 6 </u>=0

3

3 (z^2 + z -2) = 0

3(z+2)(z - 1) = 0

z + 2-2 = 0 - 2

z = -2

z - 1 + 1 = 0 + 1

z = 1

Step-by-step explanation:

  1. factor out the GCF (3) and divide everything by it, and then set it equal to zero.
  2. since you have a degree of 2, factor it into two binomials that start with the square root of the first term and end with the square root of the second term.
  3. 3=0 is extraneous solution so we leave it, then we set each binomial equal to zero to solve for z.

note: your solutions is based on the degree or the exponent of the polynomial or the function.

5 0
2 years ago
What is the variable in this expression? 5x^2 + x+7
Zinaida [17]

Answer:

its x

Step-by-step explanation:

hope it helps unlike that other person

6 0
3 years ago
If two people are randomly​ selected, what is the probability both are hopelessly romantichopelessly romantic​? what is the prob
vova2212 [387]
I'm so sorry i dont know the answer
5 0
2 years ago
Which event has exactly 12 possible outcomes?
lara [203]

Answer:

rolling a number cube with sides labeled 1 through 6 and tossing a coin.

Step-by-step explanation:

We will resolve each statement to determine the events that has exactly 12 possible outcomes.

N = number of possible outcomes for a cube

Nc = number of possible outcomes for a coin

Nca = number of possible outcomes for the cards

i. rolling a number cube with sides labeled 1 through 6 and then rolling the number cube again

Nt = N × N

N = 6 ( cube has 6 possible outcomes and its rolled twice)

Nt = 6 × 6 = 36

ii. tossing a coin and randomly choosing one of 4 different cards.

Nt = Nc × Nca

Nc = 2 ( coin has two outcomes)

Nca = 4 ( 4 possible cards )

B = 2 × 4 = 8

iii. rolling a number cube with sides labeled 1 through 6 and tossing a coin.

N = N × Nc

N = 6 ( cube has 6 possible outcomes)

Nc = 2 (coin has two faces)

N = 6 × 2 = 12 (correct)

Iv. tossing a coin 6 times.

N = Nc^6

Nc = 2

N = 2^6 = 64

Therefore, the correct answer is iii.

rolling a number cube with sides labeled 1 through 6 and tossing a coin.

3 0
3 years ago
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