20≥8+4.99x please I could get an F.

Mathematics

1 answer:

marin [14]2 years ago

5 0

Answer:

$\begin{bmatrix}\mathrm{Solution:}\:&\:x\le \frac{1200}{499}\:\\ \:\mathrm{Decimal:}&\:x\le \:2.40480\dots \\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:\frac{1200}{499}]\end{bmatrix}$

Step-by-step explanation:

$20\ge \:8+4.99x\\Switch\:sides\\8+4.99x\le \:20\\\mathrm{Multiply\:both\:sides\:by\:}100\\8\cdot \:100+4.99x\cdot \:100\le \:20\cdot \:100\\Refine\\800+499x\le \:2000\\\mathrm{Subtract\:}800\mathrm{\:from\:both\:sides}\\800+499x-800\le \:2000-800\\Simplify\\499x\le \:1200\\\mathrm{Divide\:both\:sides\:by\:}499\\\frac{499x}{499}\le \frac{1200}{499}\\Simplify\geq \\x\le \frac{1200}{499}$

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Answer:

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Step-by-step explanation:

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m_a_m_a [10]

Answer:

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Step-by-step explanation:

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Then, you need to remember that the area of a triangle can be calculated with the following formula:

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