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Lilit [14]
3 years ago
10

A miniature golf course charges different prices for adults and children. On Saturday, 50 adults and 50 children played, and the

golf course earned $800. On Sunday, 65 adults and 75 children played, and the golf course earned $1100. How much does the golf course charge for adults?
Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
3 0
{50a+50c=800
{65a+75c=1100

{15a+15c=240
{13a+15c=220

2a=20
a=10
Golf course charge for adults $10
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3 years ago
Solve the following by elimination method <br> 11x+15y+23=0 and 7x-2y-20=0
mr Goodwill [35]
Let 11x + 15y + 23 = 0 be equation (1)
And 7x - 2y - 20 = 0 be equation (2)

Multiply equation (1) by 2:
22x + 30y + 46 = 0

Multiply equation (2) by 15:
105x - 30y - 300 = 0

Add equations (1) and (2):
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127x - 254 = 0
127x = 254
x = 254/127
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Substitute x = 2 in equation (1) to find y:
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7 0
4 years ago
John uses 2/5 cup of orange juice for every 1/3 cup of pineapple juice to make a fruit punch. Write the number of cups of orange
user100 [1]
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Step by step explanation :
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6 0
2 years ago
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Answer:

A) \frac{7}{8}a

B) \frac{5}{8}a

Step-by-step explanation:

AB has length a and is divided by points P and Q into AP , PQ , and QB , such that AP = 2PQ = 2QB

A) Therefore, AP = 2QB

QB = AP/2

The midpoint of QB = QB/2 = (AP/2)/2 = AP/4

AP = 2PQ, Therefore PQ = AP/2

Since the length of AB = a

AB = AP + PQ + QB = a

AP + AP/2 + AP/2 = a

AP + AP = a

2AP = a

AP = a/2

The distance between point A and the midpoint of segment QB = AP + PQ + QB/2 = AP + AP/2 + AP/4 = 7/4(AP)

But AP = a/2

Therefore The distance between point A and the midpoint of segment QB =  7/4(a/2)= \frac{7}{8}a

B)

the distance between the midpoints of segments AP and QB = AP/2 + PQ + QB/2 = AP/2 + AP/2 + AP/4 = 5/4(AP)

But AP = a/2

Therefore the distance between the midpoints of segments AP and QB = 5/4(AP) = \frac{5}{4} *\frac{a}{2}=\frac{5}{8}a

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Answer:

It Represents An actual length of 2 ft.

Step-by-step explanation:

4 0
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