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3 years ago

Chris drove 107 miles in two hours. How many miles can he drive in 1 hour if he maintains this speed?

Mathematics

1 answer:

tankabanditka [31]3 years ago

4 0

Answer:

53.5 miles

Step-by-step explanation:

107=2 so divide by 2 107/2 =53.5

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the height of an airplane as it descends to an airport runway is it rational ,integers, whole ,or irrational?

mario62 [17]

Rational. Not whole or integer because its an exact measurement and not irrational because it CAN be expressed as a ratio (fraction, decimal measurement )

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3 years ago

Please help me with these Algebra Questions!!

Bess [88]

Answer:

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Step-by-step explanation:

I don't see anything to solve.

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2 years ago

What is the square root of 18

kifflom [539]

Answer:

4.24

Step-by-step explanation:

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3 years ago

Plz help

inn [45]

We are given with
P(pop quiz) = 60%
P(not do homework) = 85%

And the condition that
P (pop quiz and do homework) > 5%

So,
P (pop quiz) x P (do homework)
P (pop quiz) x ( 1 - P (not do homework) )
60% x ( 1 - 85%)

The result is greater than five percent so he will not do his homework.

5 0

3 years ago

Scores on a test are normally distributed with a mean of 81.2 and a standard deviation of 3.6. What is the probability of a rand

Misha Larkins [42]

Answer:

The probability of a randomly selected student scoring in between 77.6 and 88.4 is 0.8185.

Solution:

Given, Scores on a test are normally distributed with a mean of 81.2

And a standard deviation of 3.6.

We have to find What is the probability of a randomly selected student scoring between 77.6 and 88.4?

For that we are going to subtract probability of getting more than 88.4 from probability of getting more than 77.6

Now probability of getting more than 88.4 = 1 - area of z – score of 88.4

$\mathrm{Now}, \mathrm{z}-\mathrm{score}=\frac{88.4-\mathrm{mean}}{\text {standard deviation}}=\frac{88.4-81.2}{3.6}=\frac{7.2}{3.6}=2$

So, probability of getting more than 88.4 = 1 – area of z- score(2)

= 1 – 0.9772 [using z table values]

= 0.0228.

Now probability of getting more than 77.6 = 1 - area of z – score of 77.6

$\mathrm{Now}, \mathrm{z}-\text { score }=\frac{77.6-\text { mean }}{\text { standard deviation }}=\frac{77.6-81.2}{3.6}=\frac{-3.6}{3.6}=-1$

So, probability of getting more than 77.6 = 1 – area of z- score(-1)

= 1 – 0.1587 [Using z table values]

= 0.8413

Now, probability of getting in between 77.6 and 88.4 = 0.8413 – 0.0228 = 0.8185

Hence, the probability of a randomly selected student getting in between 77.6 and 88.4 is 0.8185.

4 0

3 years ago