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3 years ago

How do I find the domain and range of a function?

Mathematics

1 answer:

4vir4ik [10]3 years ago

8 0

Domain is your x values while range is your y values

You might be interested in

The rule that maps each domain value to its range value is f(x)= ___x.

kirill115 [55]

Answer:

f(x) = 1/2x

Step-by-step explanation:

When x = -4 the output is -2

We are dividing by 2

When x = -2 the output is -1

f(x) = 1/2 x

Check when x = 2

f(2) = 1/2 (2) =1

3 0

3 years ago

Subtract -5x^2+2x-5−5x 2 +2x−5 from 7x^2-47x 2 −4.

marta [7]

Answer:

-12x^2+46x-6

Step-by-step explanation:

combine like tens and subtract then from eachother

5 0

3 years ago

I need explanations. I don't understand this. Please click on the picture.

AlekseyPX

1. find the area of the two triangles, including the shaded section. the formula for this is a=1/2bh

the height and base are both 24 inches. this is because you add the 10 from the side of the square to the 14 that is given

so:

a=1/2(24)(24)
a=(12)(24)
a=288 sq. inches

since there are two triangles, you would multiply the area by 2

a=2(288)
a=576 sq. inches

now, since you only need the unshaded section, you have to take away the shaded section, which is a square. to do this, you must calculate the area of the square and take it away from the area of both triangles.

a=576-(lw)
a=576- (10)(10)
a=576-100
a=476 sq. inches

that is your answer

5 0

3 years ago

Select all the expressions that are equivalent to - 2/5 (15-20d + 5c).

Nostrana [21]

One of them is -6+8d-2c

4 0

3 years ago

Help I cannot figure this question out.

netineya [11]

Answer:

B. x = -1 ± i

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Standard Form: ax² + bx + c = 0
Factoring
Quadratic Formula: $\displaystyle x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

Algebra II

Imaginary Numbers: √-1 = i

Step-by-step explanation:

Step 1: Define

x² + 2x = -2

Step 2: Identify Variables

Rewrite Quadratic in Standard Form [Addition Property of Equality]: x² + 2x + 2 = 0
Break up Quadratic: a = 1, b = 2, c = 2

Step 3: Solve for x

Substitute in variables [Quadratic Formula]: $\displaystyle x=\frac{-2 \pm \sqrt{2^2-4(1)(2)}}{2(1)}$
[√Radical] Evaluate exponents: $\displaystyle x=\frac{-2 \pm \sqrt{4-4(1)(2)}}{2(1)}$
Multiply: $\displaystyle x=\frac{-2 \pm \sqrt{4-8}}{2}$
[√Radical] Subtract: $\displaystyle x=\frac{-2 \pm \sqrt{-4}}{2}$
[√Radical] Factor: $\displaystyle x=\frac{-2 \pm \sqrt{-1}\sqrt{4}}{2}$
[√Radicals] Simplify: $\displaystyle x=\frac{-2 \pm 2i}{2}$
Factor: $\displaystyle x=\frac{2(-1 \pm i)}{2}$
Divide: $\displaystyle x = -1 \pm i$

3 0

3 years ago