The value of the given integral is (3x+2)^2^1 /63 +c
=
=1/3*{(3x-20)^21}/21 +c
=1/63 *(3x-21)^21 +c
=d/dx {1/3*(3x-2)^21}/21 +c
=3/3 *{21(3x-2)}/21 +c
Let u=3x-2
du= 3dx
=
=1/3
=(3x+2)^2^1 /63 +c
For more information about integrals, visit
brainly.com/question/22008756
#SPJ4
1. Convert all fractions to decimals.
7/8 = 0.875
5/12 = 0.417
11/2 = 5.5
3/4 = 0.75
4/5 = 0.8
3. Organize decimals from least to greatest.
0.417, 0.75, 0.8, 0.875, 5.5
4. Put back into fractions.
5/12, 3/4, 4/5, 7/8, 11/2.
I believe it would be 4 1/10 ,4.104, 104/25, 4.74
Answer:
Step-by-step explanation:
ok
<em>Answer:</em>
<em /><em />
<em>Step-by-step explanation:</em>
<em>I wasn't really sure what you were asking but I hope this helps.</em>