For eliminating you need to have a variable that cancels the other out and in this case 2x and -2x do. Then you want to take -3y+9y and add the numbers after the equal sign. -9+3
C. Corresponding Angles Postulate
1) -10x+y=4
Now, you should substitute x in every situation.
* x=-2 <em>=> -10*(-2)+y=4... 20+y=4... <u>y=-16</u></em>
<em />* x=-1 =>-10*(-1)+y=4... 10+y=4... <u>y=-6</u>
<u />*x=0 => -10*0+y=4... <u>y=4</u>
<u />* x=1 => -10*1+y=4... -10+y=4... <u>y=14</u>
<u />* x=2 => -10*2+y=4... -20+y=4... <u>y=24</u>
<u>2)</u> -5x-1=y
For example: x=0
-5*0-1=-1
<u>
</u>
Answer:
F is reduced by 31%
Step-by-step explanation:
F = 1/(d²)
now, we increase the distance by 20% (multiply by 1.2).
F new = 1/(1.2×d)² = 1/(1.44×d²) = (1/1.44) × (1/(d²)) =
= 1/1.44 × old F = 0.69 × old F
100 - 69 = 31%
Answer:
<em>Choice: B.</em>
Step-by-step explanation:
<u>Operations With Functions</u>
Given the functions:
![f(x)=\sqrt[3]{12x+1}+4](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7B12x%2B1%7D%2B4)
The function (g-f)(x) can be obtained by replacing both functions and subtracting them as follows:
![(g-f)(x)= \log(x-3)+6 - (\sqrt[3]{12x+1}+4)](https://tex.z-dn.net/?f=%28g-f%29%28x%29%3D%20%5Clog%28x-3%29%2B6%20-%20%28%5Csqrt%5B3%5D%7B12x%2B1%7D%2B4%29)
Operating:
![(g-f)(x)= \log(x-3)+6 - \sqrt[3]{12x+1}-4](https://tex.z-dn.net/?f=%28g-f%29%28x%29%3D%20%5Clog%28x-3%29%2B6%20-%20%5Csqrt%5B3%5D%7B12x%2B1%7D-4)
Joining like terms:
![\boxed{(g-f)(x)= \log(x-3) - \sqrt[3]{12x+1}+2}](https://tex.z-dn.net/?f=%5Cboxed%7B%28g-f%29%28x%29%3D%20%5Clog%28x-3%29%20-%20%5Csqrt%5B3%5D%7B12x%2B1%7D%2B2%7D)
Choice: B.
