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stira [4]
3 years ago
9

the length of a rectangle is 1 meter less than its width. the area of the rectangle is 42 square meters. find the dimensions of

the rectangle
Mathematics
1 answer:
Keith_Richards [23]3 years ago
5 0
Length - 6 meters
width - 7 meters
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Scateboard cost Rs450each in my local store,The shop keeper says if I buy 1 I can buyanother for only 7/9 of the normal price,ho
Whitepunk [10]

Answer:

the cost will be Rs 350

Step-by-step explanation:

The Scateboard cost Rs 450 each in the local store,The shop keeper says if I buy 1 I can buy another for only \frac{7}{9} of the normal price. We are asked to determine the cost of a second scateboard .

Hence the cost will be \frac{7}{9} of the normal cost that is

\frac{7}{9} \times 450

7 \times 50

350

the cost will be Rs 350

6 0
3 years ago
Solve the system y= 4x + 1 and 3x+2y =13
Irina18 [472]

Given :

{\qquad \sf \dashrightarrow  y= 4x + 1 \: –––– \sf \:  (i)}

{\qquad \sf \dashrightarrow   3x + 2y = 13 \: –––– \sf \:  (ii)}

Now, Substituing the value of y in equation (ii) :

{\qquad \sf \dashrightarrow   \: 3x + 2y = 13   }

{\qquad \sf \dashrightarrow   \: 3x + 2(4x + 1) = 13   }

{\qquad \sf \dashrightarrow   \: 3x + 8x + 2 = 13   }

{\qquad \sf \dashrightarrow   \: 11x + 2 = 13   }

{\qquad \sf \dashrightarrow   \: 11x  = 13 - 2   }

{\qquad \sf \dashrightarrow   \: 11x  = 11   }

{\qquad \sf \dashrightarrow   \: x  =  \dfrac{11}{11}    }

{\qquad \sf \dashrightarrow   \bf \: x  = 1   }

Now, substituting the value of x in equation (i) :

{\qquad \sf \dashrightarrow  y= 4x + 1}

{\qquad \sf \dashrightarrow  y= 4(1) + 1}

{\qquad \sf \dashrightarrow  y= 4 + 1}

{\qquad \bf \dashrightarrow  y= 5}

3 0
1 year ago
Find the value of sin(a/2) if cosa= 12/13<br>​
daser333 [38]

Answer: sin\frac{a}{2} = ± \frac{1}{\sqrt{26} }

Step-by-step explanation:

We very well know that,

cos2A=1−2sin²A

⟹ sinA = ±\sqrt{(1-} \frac{cos2A}{2} )

As required,  set A = \frac{a}{2}   &   cos a=  \frac{12}{13}    ,thus we get

sin \frac{a}{2} =± \sqrt{\frac{1-cos a}{2} }  

∴ sin\frac{a}{2} =±\sqrt{\frac{1-\frac{12}{13} }{2} } = ± \frac{1}{\sqrt{26} }

   since ,360° < \frac{a}{2} <450°

             ,180° < \frac{a}{2} <225°

Now, we are to select the value with the correct sign. It's is obvious from the above constraints that the angle a/2 lies in the III-quadrant where 'sine' has negative value, thus the required value is negative.

hope it helped!

   

5 0
2 years ago
PLEASE HELP ME UwU
klasskru [66]
The answer is obviously 100 that was so easy
3 0
3 years ago
Read 2 more answers
Write an inequality to represent each sentence. Use n for the variable.
Zepler [3.9K]

Answer:

17>n is the correct answer

7 0
2 years ago
Read 2 more answers
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