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riadik2000 [5.3K]
3 years ago
10

What is the equation of the following direct variation?

Mathematics
1 answer:
balandron [24]3 years ago
4 0

Answer:

y = -2x

Step-by-step explanation:

A "direct variation" relationship has the form y = kx, where k is the "constant of proportionality.

Note that this graph goes thru the origin (which it must, to represent direct variation), and that it has a steep negative slope.  That narrows down the answer choice to the first one:  y = -2x.

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8th Grade Homework-
ahrayia [7]

Answer:

d option

Step-by-step explanation:

of course it is Charlie as he just walked 11.8 miles

please mark me as brainlist

5 0
2 years ago
Please answer this probability question.
svet-max [94.6K]

Answer:

C

Step-by-step explanation:

its 2/5 for the evens 3/5 for odds multiply and you get 6/25

7 0
3 years ago
Blanca runs 8 laps around the track each day to train for an endurance race. She times each lap to practice her pacing for the r
Artist 52 [7]

Answer:

A graph shows lap time (seconds) labeled 82 to 98 on the horizontal axis and the number of laps on the vertical axis. 1 lap was 82 to 84 seconds.  4 laps were 84 to 86 seconds. 2 laps were 86 to 88 seconds. 4 laps were 88 to 90 seconds. 6 laps were 90 to 92 seconds. 5 laps were 92 to 94 seconds. 2 laps were 94 to 96 seconds. 0 laps were 96 to 98 seconds

Step-by-step explanation:

The given table is presented as follows;

\begin{array}{ccc}Day \ 1 \ lap \ times \ (seconds)&Day \ 2 \ lap \ times \ (seconds)&Day \ 3 \ lap \ times \ (seconds)\\83&87&85\\92&90&86\\91&92&91\\89&91&93\\94&92&91\\93&95&89\\88&90&88\\84&85&84\end{array}The number of laps in the range 82 to 84 seconds = 1

The number of laps in the range 84 to 86 seconds = 4

The number of laps in the range 86 to 88 seconds = 2

The number of laps in the range 88 to 90 seconds = 4

The number of laps in the range 90 to 92 seconds = 6

The number of laps in the range 92 to 94 seconds = 5

The number of laps in the range 94 to 96 seconds = 2

The number of laps in the range 96 to 98 seconds = 0

Therefore, the histogram that represents Blanca's lap times for the three days of practice is described as follows;

A graph shows lap time (seconds) labeled 82 to 98 on the horizontal axis and the number of laps on the vertical axis. 1 lap was 82 to 84 seconds.  4 laps were 84 to 86 seconds. 2 laps were 86 to 88 seconds. 4 laps were 88 to 90 seconds. 6 laps were 90 to 92 seconds. 5 laps were 92 to 94 seconds. 2 laps were 94 to 96 seconds. 0 laps were 96 to 98 seconds

5 0
2 years ago
3. Find two possible lengths for CD if C, D, and E
Kaylis [27]

Given :

C, D, and E  are col-linear, CE = 15.8 centimetres, and DE=  3.5 centimetres.

To Find :

Two possible lengths for CD.

Solution :

Their are two cases :

1)

When D is in between C and E .

.                   .           .

C                  D          E

Here, CD = CE - DE

CD = 15.8 - 3.5 cm

CD = 12.3 cm

2)

When E is in between D and C.

.       .                .

D      E              C

Here, CD = CE + DE

CD = 15.8 + 3.5 cm

CD = 19.3 cm

Hence, this is the required solution.

3 0
3 years ago
Find the missing values for the exponential function represented by the table below.
postnew [5]

Answer:

d. 13.5, 20.25

Step-by-step explanation:

An exponential function is monotonic and does not change sign. On this basis alone, the first three choices can be eliminated.

The common ratio is 6/4 = 3/2.

The term in the sequence after 9 is 9·(3/2) = 27/2 = 13.5.

The term in the sequence after 27/2 is (27/2)·(3/2) = 81/4 = 20.25.

8 0
3 years ago
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