Answer:
Step-by-step explanation:
two intersecting lines :- one
one line:- infinite
two parallel lines:- no solution.
Literally only the first one is correct.
Answer:
m∠QPR = 35° m∠QPM =40° m∠PRS = 30°
Step-by-step explanation:
ΔPRQ is a right triangle with right angle at R. So m∠QPR = 90 - 55 = 35
ΔQPM is a right triangle with right angle at M. So m∠QPM = 90 - 40 = 40
Arc RQ = 2(35) = 70 and arc SR = 2(25) = 50.
So arc PS = 180 - (arc RQ + arc SR) = 180 - (70 + 50) = 180 - 120 = 60
Now arc PS is the intercepted arc for ∠PRS.
Therefore, m∠PRS = 60/2 = 30
I used the fact that an inscribed angle has a measure 1/2 the measure of the intercepted arc several times. Also, I used the fact that the acute angles of a right triangle are complementary. And, finally I used the fact that an inscribed angle in a semicircle is a right angle.
I hope this helped.
The awnser is 367.38 to the 3rd power only if its volume but if its surface area then it would be to the 3rd power. do u get it?
Answer:
Sine, cosine and tangent formulas are used in RIGHT triangles. So you have one 90 degree angle and two acute angles that add up to 90 degrees (they are complimentary). So the cosine of one angle would be the same as the sine of the compliment to that angle... and vice versa. To answer this question, sin 81 = cos 9, since 81 and 9 are the two acute angles of the triangle and they both add up to 90 degrees. "Cos 9" is the answer when you wish to write "sin 81" in terms of "cosine."
Please give me brainiest
