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2 years ago

Write a quadratic equation with the given roots. Write the equation in the form ax? + bx + c = 0, where a, b,

Mathematics

1 answer:

Gwar [14]2 years ago

6 0

Answer:(x^2 + 6x+5)

Step-by-step explanation : eso es porque es los primeros numeros sumados que te dan -5 y la multiplicacion -1 $x^{2} + 6x + 5$

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Use the graph of y=sin theta to find the value of 2theta for theta = pi/4 radians

Mariana [72]

We have that
y=sin x

for x=2theta
<span>theta = pi/4 radians
so
x=2*pi/4-----> x=pi/2

using a graph tool
see the attached figure

for x=pi/2
y=sin pi/2------> y=1
</span>
the solution is
1

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write an equation for a circle with a diameter that has endpoints at (-4, -7) and (-2, -5). round to the nearest tenth if necess

andrezito [222]

Answer:

The answer to your question is (x + 3)² + (y + 6)² = 2

Step-by-step explanation:

Endpoints (-4, -7) and (-2, -5)

Process

1.- Find the length of the radius

d = $\sqrt{(x2 - x1)^{2} + (y2 - y1)^{2} }$

d = $\sqrt{(-2 + 4)^{2}+ (-5 + 7)^{2} }$

d = $\sqrt{2^{2} + 2^{2} }$

d = $\sqrt{4 + 4}$

d = $\sqrt{8}$

Radius = $\frac{\sqrt{8} }{2}$ = $\sqrt{2}$

2.- Find the center

Xm = $\frac{-4 - 2}{2} = \frac{-6}{2} = -3$

Ym = $\frac{-7 - 5}{2} = \frac{-12}{2} = -6$

Center = (-3, -6)

3.- Write the equation

(x - h)² + (y - k)² = r²

(x + 3)² + (y + 6)² = ( $\sqrt{2}$ )²

(x + 3)² + (y + 6)² = 2

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Answer:

Step-by-step explanation:

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