Question

The length of the sides of a triangular garden are 10m 11m 13m.Find the measure of the angle opposite the longest side to the nearest tenth of a degree

Answer 1

C^2=a^2+b^2-2abcosC
13^2=10^2+11^2-2×10×11×cos(°)
169=100+121-220cos(°)
220cos(°)=100+121-169
220cos(°)=52
cos(°)= 13/55
°=cos-1(13/55)
°=76.328°