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Arte-miy333 [17]
4 years ago
9

A recessive allele inherited in a Mendelian manner causes the disease cystic fibrosis. A phenotypically normal man whose father

had cystic fibrosis, and a mother who comes from a long line of non-affected people, marries a phenotypically normal woman from outside the family. If the frequency in the general population of heterozygotes for cystic fibrosis is 1 in 25, what is the chance that the couple's first child will have cysitc fibrosis
Biology
1 answer:
Cloud [144]4 years ago
8 0

Answer:

The chance that the couple's first child will have cystic fibrosis = 1/100

Explanation:

Since both parents are phenotypically normal, it means that they are both heterozygous for cystic fibrosis.

The probability of a cross of two heterezygotes for a recessive allele to produce an offspring having two recessive alleles is 1 : 4 in accordance with Mendelian inheritance.

The initial probability of the couple's first child to be have two allelic pairs for cystic fibrosis = 1 : 4.

However, the frequency in the general population of heterozygotes for cystic fibrosis is 1 in 25.

Therefore, the chance that the couple's first child will have cystic fibrosis = 1/4 * 1/25 = 1/100

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