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marishachu [46]
3 years ago
15

Solve for x, assuming a, b, and c are negative constants. (ax + b)/c ≤ b

Mathematics
1 answer:
Rudik [331]3 years ago
5 0
(ax + b)/c ≤ b

ax+b ≤ cb

ax ≤ cb - b

x ≤ (cb-b)/a
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If a right triangle's hypotenuse is 17 units long, and one of its legs is 15 units long, how long is the other leg?
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So, there's a formula we can apply to right-angled triangles: Pythagorean's theorem. It states that  c = \sqrt{{a}^2 + b^{2} }, where <em>c</em> is the hypotenuse and <em>a</em> and <em>b </em>are the legs of the triangle.

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b = \sqrt{{17}^2-{15}^2}\\b = \sqrt{289-225}\\b = \sqrt{64}\\b = 8

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<em />c = \sqrt{{a}^2+{b}^2}}\\c = \sqrt{{15}^2+{8}^2}\\c = \sqrt{225+64}\\c = \sqrt{289}\\c = 17\\<em />

So, we got our hypotenuse to equal 17 units, which is correct! So, our <em>b</em> is correct too. Awesome

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