It’s unsolvable with out more context. What’s the rest of the problem.
What is the interquartile range of the data set below? Growth in feet of oak trees: 68,80,73,90,120,94,76,112,101,94,72 (1) 22
sdas [7]
<span>68,80,73,90,120,94,76,112,101,94,72 --->
68, 72, 73, 76, 80, 90, 94, 94, 101, 112, 120
Median = 90
Lower Median = 73
Upper Median = 101
IQR = 101 - 73
IQR = 28</span>
Answer:
RS 14400
Step-by-step explanation:
Given the following :
Principal sum = RS 40000
Rate = 2 paisa per 2 rupee per month
Interest at the end of 3 years
1 rupee = 100 paisa
2 Paisa per 2 rupee per month :
2/200 per month = 1 / 100 per month,
Hence rate = 0.01 = 1% monthly
Annual rate = 1% × 12 = 12 % = 0.12
Simple interest :
Principal × rate × time
40000 × 0.12 × 3
40000 × 0.36
= RS 14,400
Answer: 
Step-by-step explanation:
Given : In a sociology class there are 14 sociology majors and 11 non-sociology majors.
Total students = 14+11=25
Number of students are randomly selected = 3
Then, the number of ways to select 3 students from 25 students :-
Number of ways to select at least 2 of the 3 students re non-sociology majors :-
The probability that at least 2 of the 3 students selected are non-sociology majors will be :-
