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Simora [160]
3 years ago
12

Use the equation y=-3x if the x-value is 2 1/3

Mathematics
2 answers:
Svetllana [295]3 years ago
6 0

Answer:

y=-7

Step-by-step explanation:

-3*2 1/3 = -7 and that equals to y.

disa [49]3 years ago
5 0

Answer:

y=-7

Step-by-step explanation:

Multiply -3 times 2 1/3

Hope this helps!

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Identify the slope y-intercept of the function y= -2x + 3.​
Anna11 [10]

Answer:

First option.

Step-by-step explanation:

Use the formula y = mx + b.

Where m is the slope, and b is the y-intercept.

y = -2x + 3

The slope is -2. The y-intercept is (0, 3).

5 0
3 years ago
What is the approximate volume of a cylinder with a diameter of 12 meters and a height of 7 meters? Use 3.14 for pi.
storchak [24]
The mathematical equation for volume of a cylinder is pi times radius Squared Times height

The radius squared is 36

So 3.14 x 36 =113.04
Then you multiply 113.04 x 7 = 719.28.
Round that number and you get to 791.3.

So the answer is c
8 0
3 years ago
S.O.S help !!!!!!!!!!!!!!!!
Svetradugi [14.3K]
It means on the 4th day, 88 boats will pass. So the 3rd answer down is correct.
4 0
3 years ago
I know you want to answer this question.
Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

\frac{1}{2} ^{x-4} - 3 = 4^{x-3} - 2

First, convert 4^{x-3} to base 2:

4^{x-3} = (2^{2})^{x-3}

\frac{1}{2} ^{x-4} - 3 = (2^{2})^{x-3} - 2

Next, convert \frac{1}{2} ^{x-4} to base 2:

\frac{1}{2} ^{x-4} = (2^{-1})^{x-4}

(2^{-1})^{x-4} - 3 =  (2^{2})^{x-3} - 2

Apply exponent rule: (a^{b})^{c} = a^{bc}:

(2^{-1})^{x-4} = 2^{-1*(x-4)}

2^{-1*(x-4)} - 3 = (2^{2})^{x-3} - 2

Apply exponent rule: (a^{b})^{c} = a^{bc}:

(2^{2})^{x-3} = 2^{2(x-3)}

2^{-1*(x-4)} - 3 = 2^{2(x-3)} - 2

Apply exponent rule: a^{b+c} = a^{b}a^{c}:

2^{-1(x-4)} = 2^{-1x} * 2^{4}, 2^{2(x-3)} = 2^{2x} * 2^{-6}

2^{-1 * x} * 2^{4} - 3 = 2^{2x} * 2^{-6} - 2

Apply exponent rule: (a^{b})^{c} = a^{bc}:

2^{-1x} = (2^{x})^{-1}, 2^{2x} = (2^{x})^{2}

(2^{x})^{-1} * 2^{4} - 3 = (2^{x})^{2} * 2^{-6} - 2

Rewrite the equation with 2^{x} = u:

(u)^{-1} * 2^{4} - 3 = (u)^{2} * 2^{-6} - 2

Solve u^{-1} * 2^{4} - 3 = u^{2} * 2^{-6} - 2:

u^{-1} * 2^{4} - 3 = u^{2} * 2^{-6} - 2

Refine:

\frac{16}{u} - 3 = \frac{1}{64}u^{2} - 2

Add 3 to both sides:

\frac{16}{u} - 3 + 3 = \frac{1}{64}u^{2} - 2 + 3

Simplify:

\frac{16}{u} = \frac{1}{64}u^{2} + 1

Multiply by the Least Common Multiplier (64u):

\frac{16}{u} * 64u = \frac{1}{64}u^{2} + 1 * 64u

Simplify:

\frac{16}{u} * 64u = \frac{1}{64}u^{2} + 1 * 64u

Simplify \frac{16}{u} * 64u:

1024

Simplify \frac{1}{64}u^{2} * 64u:

u^{3}

Substitute:

1024 = u^{3} + 64u

Solve for u:

u = 8

Substitute back u = 2^{x}:

8 = 2^{x}

Solve for x:

x = 3

4 0
3 years ago
Find the x and y intercepts if the function
Tresset [83]
I belive there is none because it lands on the origin for y.
7 0
3 years ago
Read 2 more answers
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