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2 years ago

7

in a mixture of 48 litres the ratio of milk and water is 7:5. what is the quantity of milk in the mixture

1 answer:

Ratling [72]2 years ago

7 0

consider the quantity of water is X respectively,

now

7/5= 48/X, = X= 48×5/7 = 34.28 ltr.

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CONDITIONAL PROBABILITY ASSISTANCE

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Consider such events:

A - selected student is freshmen

B - selected student is girl

$A\cap B$ - selected student is freshman is girl

$A|B$ - choosen girl is freshmen.

Use formula $Pr(A|B)=\dfrac{Pr(A\cap B)}{Pr(B)}$ .

From the table you can see that girls that are freshmen are 4 from all 30 people, then $Pr(A\cap B)=\dfrac{4}{30}$ . There are 18 girls, then $Pr(B)=\dfrac{18}{30}$ . Substitute into the formula:

$Pr(A|B)=\dfrac{\frac{4}{30} }{\frac{18}{30} }=\dfrac{4}{18} =\dfrac{2}{9}$ .

Answer: $Pr(A|B)=\dfrac{2}{9}$ .

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Endpoints of segment MN have coordinates (0, 0), (5, 1). The endpoints of segment AB have coordinates (1 1/22 , 2 1/4 ) and (−2

Nana76 [90]

Answer: $k=18\dfrac{8}{11}$ .

Step-by-step explanation:

If a line passing through two points, then

$Slope=\dfrac{y_2-y_1}{x_2-x_1}$

Endpoints of segment MN have coordinates (0, 0) and (5, 1).

Slope of MN $=\dfrac{1-0}{5-0}=\dfrac{1}{5}$

The endpoints of segment AB have coordinates $\left(1\dfrac{1}{22} , 2\dfrac{1}{4}\right)$ and $\left(-2\dfrac{1}{4} , k\right)$ .

$A=\left(1\dfrac{1}{22} , 2\dfrac{1}{4}\right)=\left(\dfrac{23}{22} ,\dfrac{9}{4}\right)$

$B=\left(-2\dfrac{1}{4} , k\right)=\left(-\dfrac{9}{4} , k\right)$ .

Slope of AB $=\dfrac{k-\frac{9}{4}}{-\frac{9}{4}-\dfrac{23}{22}}$

$=\dfrac{\frac{4k-9}{4}}{\frac{-99-46}{44}}$

$=\dfrac{4k-9}{4}\times \dfrac{44}{-145}$

$=4k-9\times \dfrac{11}{-145}$

$=\dfrac{44k-99}{-145}$

Product of slopes of two perpendicular segments is -1.

Slope of MN × Slope of AB = -1

$\dfrac{1}{5}\times \dfrac{44k-99}{-145}=-1$

$\dfrac{44k-99}{-725}=-1$

$44k-99=725$

$44k=725+99$

$k=\dfrac{824}{44}$

$k=\dfrac{206}{11}$

$k=18\dfrac{8}{11}$

Therefore, the value of k is $k=18\dfrac{8}{11}$ .

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