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marysya [2.9K]
3 years ago
15

the periodic table arranges the elementsa. according to number of nuclei.b. according to atomic state.c. according to atomic num

ber
Biology
1 answer:
Pavel [41]3 years ago
4 0
It is the atomic number by which the periodic table of elements is arranged. (C, <span>according to atomic number).</span>
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At which depth below Earth's surface is the density most likely 9.5 grams per cubic centimeter​
SashulF [63]

Answer:

The options:

A. 1,500 km

B. 2,000 km

C. 3,500 km

D. 6,000 km

THE CORRECT ANSWER IS C.

C. 3,500 km

Explanation:

It's around 3,500 km beneath the Earth's surface.

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3 years ago
How does energy change when two objects collide? Think about how potential and kinetic energy work, Explain HELP PLZz!!​
Sholpan [36]

As you can see, when objects collide, or bump into each other, it causes the objects' energy to move and change. Objects that have potential energy, or stored energy, are set into motion through collision, and the energy transfers into kinetic energy, the energy of an object in motion.

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3 years ago
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In humans there is a dominant allele (A) for the absence of moles; while the recessive allele (a) results in the presence of mol
Art [367]

Answer:

a. (p + q)^7 = p^7q^0+7p^6q+21p^5q^2+35p^4q^3+35p^3q^4+21p^2q^5+7pq^6+p^0q^7

b. i. 0.75

   ii. 0.000061

   iii. 0.012

   iv. 0.17

c. 0.67

Explanation:

a. The expansion of the binomial (p + q)7 would be such that:

(p + q)^7 = p^7q^0+7p^6q+21p^5q^2+35p^4q^3+35p^3q^4+21p^2q^5+7pq^6+p^0q^7

b. Both couples are heterozygous:

             Aa    x    Aa

         AA   Aa   Aa   aa

Since A is dominant over a,

probability of having mole (aa) = 1/4

probability of not having moles = 3/4

<em>Therefore, the probability of the first child not having moles </em>= 3/4 or 0.75

ii. Let the probability of not having mole = p and the probability of having mole = q. From the binomial expansion:

(p + q)^7 = p^7q^0+7p^6q+21p^5q^2+35p^4q^3+35p^3q^4+21p^2q^5+7pq^6+p^0q^7

<em>Probability that all of the children will have moles </em>= p^0q^7

since p = 3/4 and q = 1/4

p^0q^7 = (3/4)^0(1/4)^7 = 0.000061

iii. <em>Probability that the first two children will have no moles and the last five will have moles</em> = 21p^2q5

                       = 21(3/4)^2(1/4)^5

                         = 0.012

iv. <em>Probability that 4 will have no moles and 3 will have moles out of the 7 children</em> = 35p^4q^3

               = 35(3/4)^4(1/4)^3

                      = 0.17

c. <em>Probability that the child born without moles is a carrier of the a-allele  = probability of heterozygou</em>s.

From the cross in (b), the genotypes of those born without moles are AA and 2Aa. Therefore, the probability of not having moles and be Aa is:

      = 2/3 or 0.67

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3 years ago
A stretch of DNA with instructions for one trait. *
astra-53 [7]
The answer is b, genes
6 0
3 years ago
Ill give a special golden crown!!
enyata [817]

I'm pretty sure it's the third option.

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3 years ago
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