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shepuryov [24]
4 years ago
9

The movie theater is twice as far from the school as the mall. If the movie theater is to the right of the school, which locatio

n is the movie theatee
Mathematics
2 answers:
stellarik [79]4 years ago
7 0
I see no map in front of me, but if we assume that the school is at coordinates of (0,0), and since the distance to the movie theater is to the right and double that of the mall, then we can say that the movie theater is along the x-axis, and  between the I and IV quadrants, and the location on the axis is Md2, or Mall Distance times 2.
Anuta_ua [19.1K]4 years ago
6 0
It is to the right of the school (like it says in the question). We would need a map or a graph or some options to figure the answer out.
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\displaystyle\\f(x)=3x^2+1\\g(x)=1-x\\\\(f-g)(x)=f(x)-g(x)=3x^2+1-(1-x)=3x^2+1-1+x=\boxed{3x^2+x}\\\\(f-g)(2)=f(2)-g(2)=3\cdot2^2+2=3\cdot4+2=12+2=\boxed{14}




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