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soldi70 [24.7K]
3 years ago
7

a basketball court measures 94 feet in length and w feet in width. it's perimeter is 288 feet. which value of w makes the equati

on 2(94) + 2w = 288 true? A.50ft B. 55 feet C. 65 feet D. 60 feet
Mathematics
1 answer:
zhuklara [117]3 years ago
5 0
It is 50 a im hoping it is
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Choose 5 cards from a full deck of 52 cards with 13values (2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K, A) and 4 kinds(spade, diamond, h
Delvig [45]

Answer:

a) 182 possible ways.

b) 5148 possible ways.

c) 1378 possible ways.

d) 2899 possible ways.

Step-by-step explanation:

The order in which the cards are chosen is not important, which means that we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question, we have that:

There are 52 total cards, of which:

13 are spades.

13 are diamonds.

13 are hearts.

13 are clubs.

(a)Two-pairs: Two pairs plus another card of a different value, for example:

2 pairs of 2 from sets os 13.

1 other card, from a set of 26(whichever two cards were not chosen above). So

T = 2C_{13,2} + C_{26,1} = 2*\frac{13!}{2!11!} + \frac{26!}{1!25!} = 182

So 182 possible ways.

(b)Flush: five cards of the same suit but different values, for example:

4 combinations of 5 from a set of 13(can be all spades, all diamonds, and hearts or all clubs). So

T = 4*C_{13,5} = 4*\frac{13!}{5!8!} = 5148

So 5148 possible ways.

(c)Full house: A three of a kind and a pair, for example:

4 combinations of 3 from a set of 13(three of a kind ,c an be all possible kinds).

3 combinations of 2 from a set of 13(the pair, cant be the kind chosen for the trio, so 3 combinations). So

T = 4*C_{13,3} + 3*C_{13.2} = 4*\frac{13!}{3!10!} + 3*\frac{13!}{2!11!} = 1378

So 1378 possible ways.

(d)Four of a kind: Four cards of the same value, for example:

4 combinations of 4 from a set of 13(four of a kind, can be all spades, all diamonds, and hearts or all clubs).

1 from the remaining 39(do not involve the kind chosen above). So

T = 4*C_{13,4} + C_{39,1} = 4*\frac{13!}{4!9!} + \frac{39!}{1!38!} = 2899

So 2899 possible ways.

4 0
3 years ago
I need help on number 15
garri49 [273]
Okay, you now a triangle has 180º degrees and to add to 180º, you have to add all the numbers you have like this:
2x+x+90 (the box is 90º)=180º; add like terms like 2x+x
3x+90=180; cancel 90 by subtracting it and also subtract 90 from 180
3x=90;divide 3 to isolate x and also divide 90/3
x=30 :)
3 0
3 years ago
A to the power of 6 multiplied by a to the power of 3
Kobotan [32]
Multiply and combine similar variables, using the rules of exponents. So your answer is A to the power of 9.

Hope this helped, and if it did I'd appreciate if you marked me as brainliest as I need it to get to a higher rank. If you need any more help, feel free to add me and/or message me :)
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Which is the equation of the line? Mid-Unit Test A. 3x + y = 9 B. x – y = 9 C. 3x – y = 9 D. x + 3y = 9
nirvana33 [79]
I think the answer would be D
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3 years ago
A line contains the points
Margarita [4]
What is the question?
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