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3 years ago

The area of a circular trampoline is 115.88 square feet. What is the radius of the trampoline? Round to the nearest hundredth.

1 answer:

3 0

$\bf \textit{area of a circle}\\\\
A=\pi r^2~~
\begin{cases}
r=radius\\
-----\\
A=115.88
\end{cases}\implies 115.88=\pi r^2
\\\\\\
\cfrac{115.88}{\pi }=r^2\implies \sqrt{\cfrac{115.88}{\pi }}=r$

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Given the linear function k(x) = 12 and m(x) = 3x - 5, find the new function j(x) = k(x) * m(x).

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J(x) = 12(3x - 5)
j(x) = 36x - 60
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3 years ago

The data set represents a month-to-month progression of gasoline prices over the course of several months in an unspecified city

Tresset [83]

The quadratic regression equation for this data set is $\rm y=-0.143x^2+0.59x+2.82\\$ .

<h3>What is the general form of a quadratic equation?</h3>

The general form of the quadratic equation is given by;

$\rm ax^2+bx+c=0$

Where; a, b, and c are the constants.

x; 0 1 2 3 4 5

y; 2.82 3. 29 3. 46 3. 33 2. 88 2. 24

From the table when the value of x = 0 the value of y is 2.82.

Then,

$\rm y=ax^2+bx+c\\\\x=0\\\\2.82=a0^2+b(0)+c\\\\c=2.82$

From the table when the value of x = 3 the value of y is 3.33.

$\rm y=ax^2+bx+c\\\\x=3\\\\2.82=a(3)^2+b(3)+c\\\\9a+3b+2.82=2.82\\\\9a=-3b\\\\b=-3a\\\\$

From the table when the value of x = 5 the value of y is 2.24.

$\rm y=ax^2+bx+c\\\\x=3\\\\2.24=a(5)^2+(-3a)(5)+c\\\\25a-15a+2.82=2.24\\\\40a=2.24-2.82\\\\10a=-0.68\\\\a= \dfrac{-0.68}{10}\\\\a=-0.143$

And the value of b is;

$\rm b=3a\\\\b=3(-0.14)\\\\b=0.59$

Therefore,

The quadratic regression equation for this data set is;

$\rm y=ax^2+bx+c\\\\y=-0.143x^2+0.59x+2.82\\\\$

Hence, the quadratic regression equation for this data set is $\rm y=-0.143x^2+0.59x+2.82\\$ .

To know more about the Quadratic equation click the link given below.

brainly.com/question/14935613

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2 years ago

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May I ask if you have a picture of the question or?

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3 years ago

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Savatey [412]

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3 years ago

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Zigmanuir [339]

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