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Ira Lisetskai [31]
4 years ago
9

What is the square root of 999?

Mathematics
2 answers:
matrenka [14]4 years ago
7 0

The square root is 31.6069

Doss [256]4 years ago
5 0

Answer:

Step-by-step explanation:

31.6069613

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A circular pond has a diameter of 17 feet. There is pathway around the rim of the pond. What is the length of the pathway?
NeX [460]

Answer:

53.38ft

Step-by-step explanation:

By it asking the length of the pathway, in math terms its just asking you the circumfrence of the pond.

C = 2(\pi)(r)

C = 2(3.14)(17/2)

C = 2(3.14)(8.5)

C = 53.38ft

6 0
3 years ago
Read 2 more answers
The value of y varies directly with x. If x = 15, then y = 12. What is the value of y, when x = 21?
Andrei [34K]

Answer: 16.8

Step-by-step explanation: if x= 15 and y =12 we know that y =.8 of x or 4/5 of x.  Knowing this we can divide x (21) by 5 and get 4.2.  We can then multiply this and get 16.8 which is 4/5 of x(21).  y=16.8

8 0
3 years ago
HELPPP Here's a graph of a linear function. Write the equation that describes that function.
tangare [24]

Answer:

y= 2/3x -1

Step-by-step explanation:

7 0
4 years ago
What is the arithmetic mean of the following<br> numbers?<br> 10,6, 4, 4, 6, 4, 1
slamgirl [31]

Answer:

5

Step-by-step explanation:

When you add up the values you get 35, then you divide it by the number of numbers in the set, which is 7, so when you divide 35/7, you end up with 5.

5 0
3 years ago
Solve this trig identity step by step
LenKa [72]

The trigonometric identity (cos⁴θ - sin⁴θ)/(1 - tan⁴θ) = cos⁴θ

<h3>How to solve the trigonometric identity?</h3>

Since (cos⁴θ - sin⁴θ)/(1 - tan⁴θ) = [(cos²θ)² - (sin²θ)²]/[1 - (tan²θ)²]

Using the identity a² - b² = (a + b)(a - b), we have

(cos⁴θ - sin⁴θ)/(1 - tan⁴θ) = [(cos²θ)² - (sin²θ)²]/[1 - (tan²θ)²]

= (cos²θ - sin²θ)(cos²θ + sin²θ)/[(1 - tan²θ)(1 + tan²θ)] =

= (cos²θ - sin²θ) × 1/[(1 - tan²θ)sec²θ] (since (cos²θ + sin²θ) = 1 and 1 + tan²θ = sec²θ)

Also, Using the identity a² - b² = (a + b)(a - b), we have

(cos²θ - sin²θ) × 1/[(1 - tan²θ)sec²θ] = (cosθ - sinθ)(cosθ + sinθ)/[(1 - tanθ)(1 + tanθ)sec²θ]

= (cosθ - sinθ)(cosθ + sinθ)/[(cosθ - sinθ)/cosθ × (cosθ + sinθ)/cosθ × sec²θ]

= (cosθ - sinθ)(cosθ + sinθ)/[(cosθ - sinθ)(cosθ + sinθ)/cos²θ × 1/cos²θ]

= (cosθ - sinθ)(cosθ + sinθ)cos⁴θ/[(cosθ - sinθ)(cosθ + sinθ)]

= 1 × cos⁴θ

= cos⁴θ

So, the trigonometric identity (cos⁴θ - sin⁴θ)/(1 - tan⁴θ) = cos⁴θ

Learn more about trigonometric identities here:

brainly.com/question/27990864

#SPJ1

8 0
2 years ago
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