Answer:
Step-by-step explanation:
\[2~ sin^2 x+3sin x+1=0\]
\[2sin^2x+2sin x+sin x+1=0\]
2sinx(sin x+1)+1(sin x+1)=0
(sin x+1)(2 sin x+1)=0
either sin x+1=0
sin x=-1=sin 3π/2=sin (2nπ+3π/2)
x=2nπ+3π/2,where n is an integer.
or 2sin x+1=0
sin x=-1/2=-sin π/6=sin (π+π/6),sin (2π-π/6)=sin (2nπ+7π/6),sin (2nπ+11π/6)
x=2nπ+7π/6,2nπ+11π/6,
where n is an integer.
The answer is b. 2,8 and 3,11
8=3(2)+2
8=6+2
8=8
11=3(3)+2
11=9+2
11=11
D. (xy2 + 3z14)(x2y4 – 3xy2z14 + 9z28
cost of pencil = x = 0.07
and cost of eraser = y = 0.03
Step-by-step explanation:
let cost of pencil = x
and cost of eraser = y
So, we have equations:

Solving both equations to find value of x and y
Let:

Multiply eq(1) with 4 and eq(2) with 3 and subtract

Putting value of x in equation 1:

So, x= 0.07 and y = 0.03
cost of pencil = x = 0.07
and cost of eraser = y = 0.03
Keywords: System of equations
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