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Murrr4er [49]
3 years ago
13

PLEASE ANSWER BOTH OF THEM ASAP!!!!

Mathematics
2 answers:
Ne4ueva [31]3 years ago
6 0
125 and 86.8 (If I did the math correctly). Remember that the area of right triangles are base times height times 1/2. 
Annette [7]3 years ago
6 0
I know #2 is C, because lengthxwidthxheight equals volume on a regular solid object. I'm sorry I can only answer part 2.
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A boat's value over time is given as the function f(x) and graphed below. Use A(x) = 400(b)x + 0 as the parent function. Which g
ser-zykov [4K]

Answer:

Please see attached graph

Step-by-step explanation:

We know that the equation tht represents the boats avlue is given by

A(x) = 400(b)^x + 0 = 400(b)^x

A(x) = 400(b)^x

An increment in the rate of 25% a yeard is given by

b = 1.25

A(x) = 400(1.25)^x

Which graph can be seen below

3 0
3 years ago
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Solve for X kinda confused i don’t know what to do!!
sweet [91]

Answer:

16.9265381881

Step-by-step explanation:

Tangent = Opposite/Adjacent.

Thus, tan62 = x/9 --> tan62 = 1.88072646535, multiply by 9 to get x, 1.88072646535* 9 = 16.9265381881

7 0
3 years ago
I need help with solving this problem please!!!
KATRIN_1 [288]
3 is 23 degree
8 is 157 degree
7 0
3 years ago
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PLZ HELP….
MrRissso [65]
The answer should be 1003.53
6 0
3 years ago
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Mendel crossed peas having round seeds and yellow cotyledons (seed leaves) with peas having wrinkled seeds and green cotyledons.
maw [93]

Answer:

1/16

Step-by-step explanation:

This question involves two distinct genes; one coding for seed shape and the other for cotyledon color. The alleles for round seeds (R) and yellow cotyledons (Y) are dominant over the alleles for wrinkled seed (r) and green cotyledon (y) respectively.

In a cross between a truebreeding (i.e. same alleles for both genes) pea having round seeds and yellow cotyledon (RRYY) and a truebreeding pea having wrinkled seeds and green cotyledon (rryy), the F1 offsprings will all possess a heterozygous round seed and yellow cotyledon (RrYy).

The F1 offsprings (RrYy) will produce the following gametes: RY, Ry, rY, and ry. Using these gametes in a punnet square (see attached image), 16 possible offsprings will be produced in a ratio 9:3:3:1.

According to the question, 3/16 of the F2 offsprings will possess round seeds and green cotyledons, however, only 1 of them will be truebreeding i.e. RRyy. Hence, 1/16 of the F2 offsprings will be truebreeding for round seeds and green cotyledons.

3 0
3 years ago
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