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icang [17]
3 years ago
5

Please Help: 0.125r - 0.0625 + 0.25r = 0.25 + r

Mathematics
1 answer:
IRISSAK [1]3 years ago
7 0

Answer:

r=0.5

Step-by-step explanation:

0.125r+0.25r-0.0625=0.25+r

0.375r-0.0625=0.25+r

0.375r-r=0.25+0.0625

-0.625r=0.3125

r=0.3125/0.625

r=0.5

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What is the equation of the line perpendicular to y=1/3x-8 through (-1,4)?
almond37 [142]

Answer:

3x + y = 1

Step-by-step explanation:

The line that is perpendicular to y = 1/3x - 8 would have the negative reciprocal as the slope. So this means that the equation for the perpendicular line would be y = -3x + b. To find b, you can replace x and y with the coordinates from the point given (-1, 4). The equation would be 4 = -3(-1) +b. After solving this, you get 4 = 3 + b. Subtract 3 from both sides to isolate b, and you will get b = 1. When you plug this into the original equation, you get

y = -3x + 1. When put in standard form, you get 3x + y = 1.

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3 years ago
Translate ABC using the coordinate rule (x,y) -> (x-2, y+4)
Bezzdna [24]

The coordinates of all the vertices:

A = (-7,5)

B = (-5,8)

C = (-2,4)

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3 years ago
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Find an equation in slope-intercept form of the line that has slope 2 and passes through point A(-8,7)
givi [52]

Answer:

y = 2x + 23

Step-by-step explanation:

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7 0
3 years ago
How to differentiate this
Art [367]

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6 0
3 years ago
Solve the system using elimination: -3x - 3y = 12 -9x + 3y = -24<br><br>The answer is not (-1,-3)
FinnZ [79.3K]

Answer:

{x = 1, y = -5

Step-by-step explanation:

Solve the following system:

{-3 x - 3 y = 12 | (equation 1)

{3 y - 9 x = -24 | (equation 2)

Swap equation 1 with equation 2:

{-(9 x) + 3 y = -24 | (equation 1)

{-(3 x) - 3 y = 12 | (equation 2)

Subtract 1/3 × (equation 1) from equation 2:

{-(9 x) + 3 y = -24 | (equation 1)

0 x - 4 y = 20 | (equation 2)

Divide equation 1 by 3:

{-(3 x) + y = -8 | (equation 1)

{0 x - 4 y = 20 | (equation 2)

Divide equation 2 by 4:

{-(3 x) + y = -8 | (equation 1)

{0 x - y = 5 | (equation 2)

Multiply equation 2 by -1:

{-(3 x) + y = -8 | (equation 1)

{0 x+y = -5 | (equation 2)

Subtract equation 2 from equation 1:

{-(3 x)+0 y = -3 | (equation 1)

{0 x+y = -5 | (equation 2)

Divide equation 1 by -3:

{x+0 y = 1 | (equation 1)

{0 x+y = -5 | (equation 2)

Collect results:

Answer:  {x = 1 , y = -5

5 0
4 years ago
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