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Dafna1 [17]
2 years ago
9

Choose 2 axioms that allows 22 + (m + 8) to be written as m + 30

Mathematics
2 answers:
Hitman42 [59]2 years ago
3 0

commutative for addition

<span>22+(m+8)=(m+8)+22</span> then associative <span>(m+8)+22=m+(8+22)</span> <span>=m+30</span>

Katyanochek1 [597]2 years ago
3 0

Answer:

commutative - addition

associative - addition

Step-by-step explanation:


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The fourth graders are helping raise money for the local animal shelter they hoped to raise 1,000. so far they have made 465 in
vredina [299]

The fourth graders raised 175 more than 1,000 for the local animal shelter.

First, let us identify the given.

  • Target value to raise= 1,000
  • Profit from bake sale= 465
  • Profit from t-shirt sales= 710

How much money did the fourth graders raise? The sum of the profit from the bake sale and t-shirt sales determines the total money raised.  

Total money= Profit from bake sale + Profit from t-shirt sales

Total money= 465 + 710

Total money= 1175

How much more than 1,000 have the fourth graders raised? This amount is equivalent to the difference between the total money raised and the target amount, 1,000.

Total money-target amount

1175-1000= 175

You can learn more through this link brainly.com/question/24560878.

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4 0
2 years ago
A Survey of 85 company employees shows that the mean length of the Christmas vacation was 4.5 days, with a standard deviation of
GenaCL600 [577]

Answer:

The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).

Step-by-step explanation:

We have the standard deviations for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 85 - 1 = 84

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 84 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 1.989.

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.989\frac{1.2}{\sqrt{85}} = 0.26

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.26 = 4.24 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.26 = 4.76 days

The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

92% confidence interval:

Following the sample logic, the critical value is 1.772. So

M = T\frac{s}{\sqrt{n}} = 1.772\frac{1.2}{\sqrt{85}} = 0.23

The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.23 = 4.27 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.23 = 4.73 days

The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).

8 0
3 years ago
I need help please.
enot [183]

0.2 is rounded to the nearest tenth

3 0
2 years ago
Read 2 more answers
Circle A has a diameter of approximately 20 inches and an area of approximately 300 in2.
Katena32 [7]

Answer:

4. About 2,700 in2

Step-by-step explanation:

The area of a circle (A), measured in square inches, is directly proportional to the square of its diameter (d), measured in inches. That is:

A \propto d^{2}

A = k\cdot d^{2}

Where k is the constant of proportionality, dimensionless.

In consequence, the following relationship between circles A and B is obtained:

\frac{A_{B}}{A_{A}} = \frac{d_{B}^{2}}{d_{A}^{2}}

The area of the circle B is now cleared:

A_{B} =\left(\frac{d_{B}}{d_{A}} \right)^{2}\cdot A_{A}

Given that d_{A} = 20\,in, d_{B} = 60\,in and A_{A} = 300\,in^{2}, then:

A_{B} = \left(\frac{60\,in}{20\,in} \right)^{2}\cdot (300\,in^{2})

A_{B} = 2700\,in^{2}

Therefore, the correct answer is 4.

7 0
3 years ago
Ax+By=C <br> Can you guys solve this please and explain how you did it.
OleMash [197]
What variable are you solving for?
3 0
3 years ago
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