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Mrac [35]
3 years ago
5

Mr. Seymour is setting up an experiment for his math class.he's going to have five groups in his class. he gives each group some

rice. He has 4/7 cups of rice how much should be he give each group?
Mathematics
2 answers:
inn [45]3 years ago
6 0
4/35 is what i think the answer is
Setler79 [48]3 years ago
5 0
The correct answer is he should give 1/5 cups of rice to each group
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mojhsa [17]

Answer:

the correct answer is 131

Step-by-step explanation:

5^3 +3(2)

= 125 +6

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5 0
3 years ago
ASAP!!! ILL GIVE BRAINLIEST
Ostrovityanka [42]

Answer:

The correct options are 2 and 4.

Step-by-step explanation:

From the given box plot it is clear that

\text{Minimum value}=20

Q_1=25

Median=40

Q_3=50

\text{Maximum value}=110

We know that these number divides the data in four equal parts.

Q_1=25\%

Median=50%

Q_3=75\%

25% of the data values lies between 50 and 110. Therefore option 1 is incorrect.

Seventy-five percent of the data values lies between 20 and 50. Therefore option 2 is correct.

It is unlikely that there are any outliers. This statement is not true because the is a huge difference between third quartile and maximum value.

Therefore option 3 is incorrect.

The interquartile range is

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Therefore option 4 is correct.

The range is

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Therefore option 5 is incorrect.

4 0
3 years ago
Z + 81 = 9z -7 help solve
Ede4ka [16]
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Have a good day!
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5 0
3 years ago
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Virty [35]

Answer: 286 minutes

Step-by-step explanation:

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1. 39.95 + 0.10x > 0.24x

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7 0
3 years ago
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Lemur [1.5K]
15 because 10x4 is 40 divided by 2 is 20 and 20-5 =15
3 0
3 years ago
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