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creativ13 [48]
3 years ago
6

If f(x)=2x-6 and g(x)=3x+9, find (f+g)(x)

Mathematics
1 answer:
anyanavicka [17]3 years ago
7 0

Answer:

<em>(f+g)(x) </em>= 5x + 3

Step-by-step explanation:

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Given the exponential decay function
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The answer is a I hope this helps your welcome
5 0
2 years ago
A sequence is defined recursively by the formula f(n + 1) = f(n) + 3 . The first term of the sequence is –4. What is the next te
Jet001 [13]

Answer:

<h2>-1</h2>

Step-by-step explanation:

f(1)=-4\\\\f(n+1)=f(n)+3-\text{the next term is 3 bigger than the previous one}\\\\f(2)=-4+3=-1

8 0
3 years ago
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3. Which polynomial is equal to
Nataly_w [17]

Which polynomial is equal to  (-3x^2 + 2x - 3) subtracted from  (x^3 - x^2 + 3x)?

<h3><u><em>Answer:</em></u></h3>

The polynomial equal to (-3x^2 + 2x - 3) subtracted from  (x^3 - x^2 + 3x) is x^3 + 2x^2 + x + 3

<h3><u><em>Solution:</em></u></h3>

Given that two polynomials are: (-3x^2 + 2x - 3) and (x^3 - x^2 + 3x)

We have to find the result when (-3x^2 + 2x - 3) is subtracted from  (x^3 - x^2 + 3x)

In basic arithmetic operations,

when "a" is subtracted from "b" , the result is b - a

Similarly,

When (-3x^2 + 2x - 3) is subtracted from  (x^3 - x^2 + 3x) , the result is:

\rightarrow (x^3 - x^2 + 3x) - (-3x^2 + 2x - 3)

Let us solve the above expression

<em><u>There are two simple rules to remember: </u></em>

  • When you multiply a negative number by a positive number then the product is always negative.
  • When you multiply two negative numbers or two positive numbers then the product is always positive.

So the above expression becomes:

\rightarrow (x^3 - x^2 + 3x) + 3x^2 -2x + 3

Removing the brackets we get,

\rightarrow x^3 - x^2 + 3x + 3x^2 -2x + 3

Combining the like terms,

\rightarrow x^3 -x^2 + 3x^2 + 3x - 2x + 3

\rightarrow x^3 + 2x^2 + x + 3

Thus the resulting polynomial is found

5 0
3 years ago
16
vagabundo [1.1K]

Answer:

<h2>58°</h2>

Step-by-step explanation:

We will use the tangent function since we know the opposite and adjacent sides.

Tangent = opposite/adjacent

Tan(e) = 16/10

Tan(e) = 1.6

Use the inverse tangent function to find the angle.

Arctan (1.6) = 57.9946168

Rounding this we get: 58°

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3 years ago
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