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Citrus2011 [14]

3 years ago

15

What do you do to divide a decimal by a repeating decimal?

1 answer:

dimaraw [331]3 years ago

5 0

<span>make both numbers fractions then divide them as fractions and then divide the numerator by the denominator and get your answer.</span>

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Which equation represents a line perpendicular to the line shown on the graph?

xenn [34]

Answer:

the third one...............

5 0

3 years ago

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4 years ago

Solve the given equation. 5^(1/4)/125^(x/3) =1

scZoUnD [109]

Answer:

x = 0.25

Step-by-step explanation:

Rewrite the equation as:

$\frac{\sqrt[4]{5}}{125^{x/3}} = 1$

$\sqrt[4]{5} = 125^{x/3}$

$(\sqrt[4]{5})^4 = (125^{x/3})^4$

$5 = 125^{4x/3}$

$ln5 = ln(125^{4x/3})$

$ln5 = \frac{4x}{3}ln125$

$x = \frac{3}{4}\frac{ln5}{ln125} = \frac{3}{4}\frac{1}{3} = \frac{1}{4} = 0.25$

3 0

3 years ago

The derivative of the function f is given by f′(x)=−3x+4 for all x, and f(−1)=6. Which of the following is an equation of the li

Viefleur [7K]

Answer:

The equation of the line tangent to the graph of f at x = -1 is $y = 7\cdot x +13$ .

Step-by-step explanation:

From Analytical Geometry we know that the tangent line is a first order polynomial, whose form is defined by:

$y = m\cdot x + b$ (1)

Where:

$x$ - Independent variable, dimensionless.

$y$ - Dependent variable, dimensionless.

$m$ - Slope, dimensionless.

$b$ - Intercept, dimensionless.

The slope of the tangent line at $x = -1$ is:

$f'(x) = -3\cdot x +4$ (2)

$f'(-1) = -3\cdot (-1) +4$

$f'(-1) = 7$

If we know that $m = 7$ , $x = -1$ and $y = 6$ , then the intercept of the equation of the line is:

$b = y-m\cdot x$

$b = 6-(7)\cdot (-1)$

$b = 13$

The equation of the line tangent to the graph of f at x = -1 is $y = 7\cdot x +13$ .

3 0

3 years ago

Which is a y intercept of the graphed function

Basile [38]

Answer:

-9

Step-by-step explanation: It crosses the y axis. A y intercept is in when the x axis is 0. So the point would be (0,-9).

8 0

4 years ago