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ryzh [129]
3 years ago
8

Solve for n; 1.2n + 0.68 = 5

Mathematics
2 answers:
bulgar [2K]3 years ago
8 0

Answer:

n= 18 over 5

Step-by-step explanation:

kifflom [539]3 years ago
6 0

Answer: n = 3.6

Step-by-step explanation: When solving an equation that contains decimals, we want to get rid of the decimals as soon as possible.

Notice that 1.2 is taken to the tenths place

but 0.68 is taken to the hundredths place.

To get rid of all decimals in the equation, multiply both

sides by the greatest power of 10 that is required.

So here we multiply both sides by 100 which

moves all decimals 2 places to the right.

So we have (100)(1.2n + 0.68) = (5)(100).

This gives us 120n + 68 = 500.

Now subtract 68 from both sides to get 120n = 432.

Dividing both sides by 120, we find that n = 3.6.

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11/4 - 2/4 as an improper fraction
tatiyna

Answer:

9/4

Step-by-step explanation:

a improper fraction is a fraction where the numerator is a larger number then the denominator

11/4 - 2/4 would be 9/4 because 11 -2 is 9 and you keep the denominator

4 0
2 years ago
Determine all real values of p such that the set of all linear combination of u = (3, p) and v = (1, 2) is all of R2. Justify yo
Rama09 [41]

Answer:

p ∈ IR - {6}

Step-by-step explanation:

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is all R2 ⇔

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And also u and v must be linearly independent.

In order to achieve the final condition, we can make a matrix that belongs to R^{2x2} using the vectors ''u'' and ''v'' to form its columns, and next calculate the determinant. Finally, we will need that this determinant must be different to zero.

Let's make the matrix :

A=\left[\begin{array}{cc}3&1&p&2\end{array}\right]

We used the first vector ''u'' as the first column of the matrix A

We used the  second vector ''v'' as the second column of the matrix A

The determinant of the matrix ''A'' is

Det(A)=6-p

We need this determinant to be different to zero

6-p\neq 0

p\neq 6

The only restriction in order to the set of all linear combination of ''u'' and ''v'' to be R2 is that p\neq 6

We can write : p ∈ IR - {6}

Notice that is p=6 ⇒

u=(3,6)

v=(1,2)

If we write 3v=3(1,2)=(3,6)=u , the vectors ''u'' and ''v'' wouldn't be linearly independent and therefore the set of all linear combination of ''u'' and ''b'' wouldn't be R2.

7 0
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The smartest person can only help with the method please help <br> 3 1/4 divided by 2
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Answer:

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Step-by-step explanation:

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6 0
3 years ago
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Answer:

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8 0
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6 0
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