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laiz [17]
4 years ago
8

A mutant protist is found in which some mitochondria lack an inner mitochondrial membrane. Which of the following pathways would

be completely disrupted in these mitochondria?
A) oxidative phosphorylation
B) alcoholic fermentation
C) the citric acid cycle
D) glycolysis
E) biosynthesis
Biology
1 answer:
Sergeu [11.5K]4 years ago
5 0

Answer:

The correct answer is A) oxidative phosphorylation

Explanation:

The membrane which separates matrix of mitochondria from the intermembrane space is celled inner mitochondrial membrane. The inner mitochondria membrane has an electron transport chain(ETC) which helps in the process of oxidative phosphorylation.

In oxidative phosphorylation, the electrons donated by an electron donor pass through ETC which allow the transport of H+ ions into the intermembrane space from the matrix. Then when these H+ goes back to matrix through ATPase then it generates ATP.  

So oxidative phosphorylation would be completely disrupted in these mitochondria.

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Describe sexual reproduction
almond37 [142]

Answer:

Sexual reproduction is the process in which new organisms are created, by combining the genetic information from two individuals of different sexes.

Explanation:

The genetic information is carried on chromosomes within the nucleus of specialized sex cells called gametes.

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8 0
3 years ago
2. ATP releases energy when a bond is broken<br>between which of the following?​
Volgvan

Answer:phosphate

Explanation:

3 0
4 years ago
13. Dihybrid Cross
Ksju [112]

Answer:

There is 56 percent chance that the offspring will be red and tall

Explanation:

A punnet square can be described as a diagram which is used to check the outcomes of a cross.  A monohybrid cross is a cross in which a single trait is studied. A dihybrid cross is a cross in which two traits are studied and the results of an offspring having two traits are predicted.

As we see, red is dominant over white and tall is dominant over short, the results of the punnet square show that there is a 56% chance for red and tall offsprings.

9 divided by 16 and multiplied by 100 gives 56.2.

6 0
4 years ago
(b) Based on the data for the groups of cells cultured with 0.1% serum (groups 3 to 7), identify the groups(s) most likely to in
joja [24]

Answer:

Groups 4 to 7 are most likely to be undergoing the mitotic phase of the cell cycle.

Explanation:

Since the four proteins used p16,  p18,  p21, and  p27 are inhibitors of cyclin-dependent kinases (CDK), their absence indicates that the cell is undergoing mitosis - the cell cycle is regulated by CDKs. In the absence of these inhibitors, the cell cycle moves on forward. Because the bar for DNA replication is longer in the case for groups 4 to 7, it is indicative of the fact that these cells have gone through the mitotic phase.

Hope that answers the question, have a great day!

4 0
3 years ago
The function of meiosis is to produce gametes: eggs or sperm. During meiosis, a diploid (2N) mother cell undergoes two meiotic d
Andrej [43]
The error is that four haploid daughter cells are made so it needs to be 4N, because there should be 4 instead of 2
4 0
3 years ago
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