End behavior: f. As x -> 2, f(x) -> ∞; As x -> ∞, f(x) -> -∞
x-intercept: a. (3, 0)
Range: p. (-∞, ∞)
The range is the set of all possible y-values
Asymptote: x = 2
Transformation: l. right 2
with respect to the next parent function:
Domain: g. x > 2
The domain is the set of all possible x-values
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(flipped the sign because we're dividing by a negative)
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Given that ∠B ≅ ∠C.
to prove that the sides AB = AC
This can be done by the method of contradiction.
If possible let AB =AC
Then either AB>AC or AB<AC
Case i: If AB>AC, then by triangle axiom, Angle C > angle B.
But since angle C = angle B, we get AB cannot be greater than AC
Case ii: If AB<AC, then by triangle axiom, Angle C < angle B.
But since angle C = angle B, we get AB cannot be less than AC
Conclusion:
Since AB cannot be greater than AC nor less than AC, we have only one possibility. that is AB =AC
Hence if angle B = angle C it follows that
AB = AC, and AB ≅ AC.