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lilavasa [31]
3 years ago
7

‼️‼️help please ASAP ‼️

Mathematics
1 answer:
Snezhnost [94]3 years ago
5 0
Its A or 6 because 30 divided by 5 is 6
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A rectangular garden is 5 ft longer than it is wide. Its area is 500 ft2. What are its dimensions?
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the length is 25 and the width is 20

Step-by-step explanation:

5 0
3 years ago
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What are the greatest common factors of 15 and 6
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The greatest common factor is 3.


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If (a+bi)^2=2abi, what must be the relationship between a and b? Show or explain your reasoning.
Klio2033 [76]
(a+bi)^2 =(a+bi)(a+bi)= a^2 +2abi+b^2 i^2 \\  \\ i^2 = -1 \\  \\ (a+bi)^2 = a^2-b^2 +2abi = 2abi \\  \\ a^2 -b^2 = 0 \\  \\ a^2 = b^2 \\  \\ a = b

For the statement to be true, 'a' and 'b' must be equal

*First expand the binomial using FOIL, then set it equal to whats given "2abi".
Then you can find the relationship between a and b.
6 0
3 years ago
36/78 as a fraction
muminat

Answer:

6/13

Step-by-step explanation:

36/78 simplified:

36/78 ---> 18/39 --->6/13

8 0
3 years ago
Prove that csc x - cot x is the same as (sin x)/(1 + cos x)
Lera25 [3.4K]
\csc x-\cot x=\dfrac{\sin x}{1+\cos x}\\\\L_s=\dfrac{1}{\sin x}-\dfrac{\cos x}{\sin x}=\dfrac{1-\cos x}{\sin x}\\\\R_s=\dfrac{\sin x}{1+\cos x}\cdot\dfrac{1-\cos x}{1-\cos x}=\dfrac{\sin x(1-\cos x)}{1^2-\cos^2x} =\dfrac{\sin x(1-\cos x)}{1-\cos^2x}\\\\=\dfrac{\sin x(1-\cos x)}{\sin^2x}=\dfrac{1-\cos x}{\sin x}\\\\L_s=R_s

\text{Used:}\\\\\csc x=\dfrac{1}{\sin x}\\\\\cot x=\dfrac{\cos x}{\sin x}\\\\a^2-b^2=(a-b)(a+b)\\\\\sin^2x+\cos^2x=1\to\sin^2x=1-\cos^2x
8 0
3 years ago
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