Part 1)
(x²+15x+65)+(2x-5)*(3x+8)
(x²+15x+65)+(6x²+16x-15x-40)
(7x²+16x+25)
the answer Part 1) is the letter B
(7x²+16x+25)
Part 2)
(4x+1)*(3x-4)-(5x²-10x-12)
(4x+1)*(3x-4)-(5x²-10x-12)
(12x²-16x+3x-4)-(5x²-10x-12)
(7x²-3x+8)
the answer Part 2) is the letter D
(7x²-3x+8)
Part 3)
(8x²+19x+4)+(3x+2)*(x-5)
(8x²+19x+4)+(3x²-15x+2x-10)
(11x²+6x-6)
the answer part 3) is the letter A
(11x²+6x-6)
Part 4)
(6x+1)*(3x-7)-(7x²-34x-20)
(18x²-42x+3x-7)-(7x²-34x-20)
(11x²-5x+13)
the answer Part 4) is the letter C
(11x²-5x+13)
Answer:
Step-by-step explanation:
Given: Dimensions of a big locker are 0.5 m × 0.6 m × 1.2 m
Dimensions of a small locker are 0.5 m × 0.6 m × 
(as height of small locker is half the height of big locker )
To find: total volume of one big locker and one small locker
Solution:
Volume of cuboid = length × breadth × height
Total volume of one big locker and one small locker = Total volume of one big locker + total volume of one small locker
= 
Answer:
30
Step-by-step explanation:
Answer:The answer is 11.75
Step-by-step explanation:
Answer is D. last one
2 * 3 = 6
On the number line, 0 to 3, it's 3 units
then 3 to 6, there's another 3 units
so 2 x 3(units) = 6
