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3 years ago

15

What is the product?(-2d^2+s)(5d^2-6s)

1 answer:

zimovet [89]3 years ago

5 0

(-2d² + s)(5d² - 6s)

Simplify.

(-2d² × 5d²) + (-2d² × 6s) + (s × 5d²) + (s × -6s)

Simplify.

-10d² + (-12d²s) + (5d²s) + (-6s²)

Take out the parenthesis.

-10d² - 12d²s + 5d²s - 6s²

Combine like terms.

-10d² + (-12d²s + 5d²s) - 6s²

Simplify.

-10d² - 7d²s - 6s²

~Hope I helped!~

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Can someone please teach how to do this .

iren [92.7K]

Answer:

Step-by-step explanation:

Let's take for example the first one Al(C2H2O2)

If there is no subscript under the number, the amount of atoms is 1

If we have a subscript, as in this case, the subscript is the number of atoms.

In the example above, there is 1 atom of Aluminium, two of Carbon, two of Hydrogen and 2 of Oxygen. If you have parenthesis and number before them, e.g., 4(Al2O3), you just multiply the parenthesis by the number in front of them, which means 4*2=8 aluminium atoms, 3*4=12 oxygen atoms, the same applies if the number is subscript behind the parenthesis like in fourth example.

6 0

3 years ago

3. Solve each of the following constant coefficient ordinary differential equations: (10 pts] a) y"+ 3y'- 28y = 0

eduard

Answer:

$y(t) = C_1e^{4t} + C_2e^{-7t}$

Step-by-step explanation:

We are given the following information in the question:

$y''+3y'-28y = 0$

This can be written as:

$(D^2 + 3D - 28)y = 0$

The auxiliary equation obtained is:

$m^2+ 3m - 28 = 0\\ m^2 + 7m - 4m - 28 = 0\\m(m+7)-4(m+7)=0\\(m-4)(m+7)\\m = 4, m = -7$

Thus, the general solution of the equation is:

$y(t) = C_1e^{4t} + C_2e^{-7t}\\\text{where } C_1, C_2 \text{ are constants}$

6 0

3 years ago

Give the equation of a line that goes through the point ( − 24 , 2 ) and is perpendicular to the line 8 x + 3 y = − 6 . Give you

Studentka2010 [4]

Answer:

$y=\frac{3}{8}x+11$

Step-by-step explanation:

To find a line that is perpendicular to 8x + 3y = -6 and goes through (-24, 2), lets first find what the line's slope would be.

We can find this by finding the slope of 8x + 3y = -6 and taking the negative reciprocal of it.

We can find the slope of that line by putting it in slope-intercept form:

8x + 3y = -6

Subtract 8x from both sides.

3y = -6 - 8x

Divide both sides by 3.

$y=-\frac{6}{3}-\frac{8}{3}x$

$y=-\frac{8}{3}x-2$

So the slope of that line would be -8/3.

The negative reciprocal of -8/3 would be 3/8.

Now we know that the new line would have to pass through the point (-24, 2). We can use this point and write the equation in point-slope form:

$y-2=\frac{3}{8}(x+24)$

Now lets change this into slope-intercept form. Add 2 to both sides.

$y=\frac{3}{8}(x+24) +2$

Distribute the 3/8.

$y=\frac{3}{8}x+9+2$

Simplify.

$y=\frac{3}{8}x+11$

And now we have our equation in slope-intercept form.

I hope you find this helpful.

5 0

3 years ago

Evalvate functions helppp!?

AURORKA [14]

The answer is 19.. substitute -1 into the function whenever you see x put -1 there. This implies that 3+16 =19

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3 years ago

Find the unit cost of a store sells a dozen eggs for 1.99.

Charra [1.4K]

Answer: 0.16$

Step-by-step explanation: You would do 1.99 divided by 12 because 12 equals to a dozen, 1.99 divided by 12 to get 0.16 cents.

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4 years ago