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Karo-lina-s [1.5K]
3 years ago
6

If h(x)= 5 for the function h(x)= 2x+1, what is the value of x?

Mathematics
1 answer:
hodyreva [135]3 years ago
4 0
The value of x is equal to 2. 2 times 2 will give you four. if you add one to the product, you get 5
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six dollars and 30 cents

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2 and 3/8 minus 3/4 is greater than or less than 2?
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It is less than 2. I hope this helps!
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Read 2 more answers
I have no idea!! Please help!!!
Ber [7]
The area of a traingle is \frac{1}{2}bh
So we need to know the base and the height
To work out the sides of a right angle triangle we can use a²+b²=c
c is the hypotenuse and a and b are the other sides
Because this triangle is isoceles we know that a and b are the same

a²+b²=c²
a²+a²=c²
2a²=c²
2a²=(x√6)²
2a²=(x√6)(x√6)
2a²=x²+x√6+x√6+6
2a²=x²+x√6+x√6+6
a²=\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{2}
a=\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}

A=\frac{1}{2}bh
A=\frac{1}{2}a*a
A=\frac{1}{2}×\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}×\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}
A=\frac{1}{2}×\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{2}
A=\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{4}
8 0
3 years ago
Help i am confused and im not sure how to answer this
gayaneshka [121]

Answer:

y=(x-4)²

Step-by-step explanation:

(a-b)²=a²-2ab+b²

(x-4)²=x²-2×x×4+4²

(x-4)²=x²-8x+16

7 0
3 years ago
Read 2 more answers
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