The coordinates of the vertices of the image are L' = (-4, 6), M' = (-5, 1) and N' = (-7, 3)
<h3>What are the coordinates of the vertices of the image?</h3>
The vertices of the preimage of the triangle are given as:
L = (4, -6)
M = (5, -1)
N = (7, -3)
The rotation is given as: 180 degrees counterclockwise
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The rule of this rotation is
(x, y) => (-x, -y)
So, we have:
L' = (-4, 6)
M' = (-5, 1)
N' = (-7, 3)
Hence, the coordinates of the vertices of the image are L' = (-4, 6), M' = (-5, 1) and N' = (-7, 3)
Read more about rotation at:
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Answer:
x = -8
Step-by-step explanation:
(4 · x) - (4 · 6) + 6 = 6x - 2
4x - 24 + 6 = 6x - 2
4x - 18 = 6x - 2
Isolate x.
4x = 6x - 2 + 18
4x = 6x + 16
4x - 6x = 16
-2x = 16
x = 16 ÷ -2
x = -8
I hope this helps! :)
Answer:
Supplementary
Step-by-step explanation:
84 plus 96 equals 180 degrees
supplementary angles are angles that add up to 180 so their relationship is supplementary
If you mean parallel to another line, you have to find the the equation of that line. Lets just say it was y= 7x-2. To find the slope of a line parallel to that, then you look at the slope of that line, which in this case would be 7. The slope of a line parallel would have to be the same. So, I can't give you a direct answer because I can't see the graph but that is how you get the answer.
