5) The relation between intensity and current appears linear for intensity of 300 or more (current = intensity/10). For intensity of 150, current is less than that linear relation would predict. This seems to support the notion that current will go to zero for zero intensity. Current might even be negative for zero intensity since the line through the points (300, 30) and (150, 10) will have a negative intercept (-10) when current is zero.
Usually, we expect no output from a power-translating device when there is no input, so we expect current = 0 when intensity = 0.
6) We have no reason to believe the linear relation will not continue to hold for values of intensity near those already shown. We expect the current to be 100 for in intensity of 1000.
8) Apparently, times were only measured for 1, 3, 6, 8, and 12 laps. The author of the graph did not want to extrapolate beyond the data collected--a reasonable choice.
We can see that there are 5 CDs, each of radius 9 cm
<u>Area occupied by 1 disc:</u>
Area of a circle = πr²
Area of disc = π(9)²
Area of disc = 3.14 * 81 = 254 cm²
<u>Area occupied by 5 discs:</u>
Area occupied by 5 discs = Area occupied by 1 disc * 5
Area occupied by 5 discs = 254 * 5
Area occupied by 5 discs = 1270 cm²
Answer:
Analyze then add
Step-by-step explanation:
Basically, just analyze the lengths of the sides, and then add them together for the perimeter
Thank me later :)
Answer:
d. x = -3
Step-by-step explanation:
<u />
÷ (x+8)(x-2) = 0
f(x) / g(x) = 0
Variable x cannot be equal to any of the values −8,2 since division by zero is not defined. Multiply both sides of the equation by (x−2)(x+8).
<u /> = 0 ------ square both sides
x + 3 = 0
solve for x:
x = -3
