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3 years ago

What function equation is represented by the graph?

Mathematics

1 answer:

KATRIN_1 [288]3 years ago

6 0

Answer:

f(x) = -2.5x + 4

Step-by-step explanation:

If you go down 5 units and 2 units to the right then there is another point so the slope is -5/2 which is the same thing as -5 divided by 2. So it’s -2.5 as the slope and for the y- intercept, there is only one point on there and it is on 4. So the function is

f(x) = -2.5x + 4

I hope this helps

(I deserve to be marked the brainliest)

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Cos^2 2A+4sin^2A×cos^2 A=1

Nonamiya [84]

Using Sin^2 and Cos^2 identities,
= Cos^2(2A) + 4[(1/2)(1-Cos(2A)][(1/2)(1+Cos(2A)] = 1
= Cos^2(2A) + 1 -Cos^2(2A) = 1
0 = 0
There is nothing to solve for as it is an identity of sorts.

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3 years ago

Manuel's job pays $11.50 per hour for a 40-hour work week.If Manuel worls over forty hours,he earns 1.5 times his hourly pay for

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Step-by-step explanation:

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3 years ago

What is the diameter of circle T?

Ratling [72]

Answer:

$Diameter = 16$

Step-by-step explanation:

Given

$\theta = 72$

$Sector = \frac{64}{5}\pi$

Required

Calculate the diameter

The area of a sector is:

$Area = \frac{\theta}{360} * \pi r^2$

Substitute values for Area and $\theta$

$\frac{64}{5}\pi = \frac{72}{360} * \pi r^2$

Divide both sides by $\pi$

$\frac{64}{5} = \frac{72}{360} * r^2$

Make $r^2$ the subject

$\frac{64*360}{5*72} = r^2$

$\frac{64*360}{360} = r^2$

$64 = r^2$

Take positive square roots of both sides

$\sqrt{64} = r$

$8 = r$

$r = 8$

The diameter is then calculated as:

$Diameter = 2r$

$Diameter = 2*8$

$Diameter = 16$

5 0

3 years ago

Find a_1 and d for an arithmetic sequence with these terms. a_4=9and a_7=18

jonny [76]

$\bf \begin{array}{llll}
term&value\\
-----&-----\\
a_4&9\\
a_5&9+d\\
a_6&(9+d)+d\\
&9+2d\\
a_7&(9+2d)+d\\
&9+3d=\underline{18}
\end{array}\\\\
-------------------------------\\\\
9+3d=18\implies 3d=9\implies d=\cfrac{9}{3}\implies \boxed{d=3}$

$\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
n=7\\
d=3
\end{cases}
\\\\\\
a_7=a_1+(7-1)d\implies 18=a_1+(7-1)3\implies 18=a_1+18
\\\\\\
18-18=a_1\implies \boxed{0=a_1}$

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4 years ago