Answer:
B
Explanation:
Start by making a punnet square with the female’s genotype on top and the male’s along the left side. Because the traits are independent of one another, you have to put all possibilities for what the mother and the father can give to the offspring:
ST St sT st
ST SSTT SsTt SsTT SsTt
St SSTt SStt SsTt Sstt
sT SsTT SsTt ssTT ssTt
st SsTt Sstt ssTt sstt
Now for a leopard offspring to be sassy, their genotype would need to be ss because the S gene is dominant over s. Following that same logic, a timely offspring can have the genotype TT or Tt. Now we look back to the punnet square to see which squares match a sassy and timely offspring. These will be marked by a * next to it:
ST St sT st
ST SSTT SsTt SsTT SsTt
St SSTt SStt SsTt Sstt
sT SsTT SsTt ssTT* ssTt*
st SsTt Sstt ssTt* sstt
So the probability of having a sassy and timely offspring would be 3 out of a total of 16 squares. Convert that to a percentage and voila, you have your answer.
3/16 = 0.1875 x 100 = 18.75%
Products of aerobic respiration would be water and carbon dioxide
Answer:
D: A high-angle fault under compression
Explanation:
Answer:
Crossing over, independent assortment and random fusion of gametes
Explanation:
Sexual reproduction creates variations by any of the three processes:
A) Exchange of genetic material between the non-sister chromatids of homologous chromosomes during prophase I of meiosis produce new gene combinations.
B) Independent assortment of homologous chromosomes towards opposite poles during anaphase I of meiosis I produce genetic variations among the daughter cells.
C) The random fusion of the gametes formed by meiosis further add genetic variations.
