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2 years ago

What is greater 1/3 or 1/8

2 answers:

8 0

1/3 is greater. Picture a pie with nothing cut into it. Then, you cut 3 equal pieces out of it, leaving no pie remaining. So, if you take 1 piece, you have 2 pieces that you didn't take. So if you do the exact same thing, but you cut <em>8 </em>pieces out of the pie and you take 1 piece, there are still 7 pieces remaining. So 1/8 is a smaller part of the pie than the 1/3, since you are cutting the pie into 8 identical pieces while with 1/3 you are cutting the same sized pie into 3 pieces. Sorry if I was confusing, just ask me if you want an easier-to-understand explanation. Also, if you pick a "brainliest" answer, it actually <em>gives </em>you points.

True [87]2 years ago

6 0

1/3 because u would do 1/3 and 1/8 next to each other 1x3 so 1/8 equals 3 then we do 1x8 and that equals 8 so 1/3 equals 8 then u conpare them 8>3 so 1/3>1/8

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Cheryl can travel 21.6 miles on one gallon of gas. how far can cheryl travel on 6.2 gallons of gas?

boyakko [2]

21.6 miles per gallon

Multiplied by 6.2 gallons

21.6 * 6.2 = 133.92

Cheryl can travel 133.92 (or about 134) miles on 6.2 gal. of gas.

Hope that helped!

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2 years ago

Someone pls help me with this I will make you brain

never [62]

Answer:

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Step-by-step explanation:

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2 years ago

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2 years ago

What is the solution of

kobusy [5.1K]

Answer:

Third option: x=0 and x=16

Step-by-step explanation:

$\sqrt{2x+4}-\sqrt{x}=2$

Isolating √(2x+4): Addind √x both sides of the equation:

$\sqrt{2x+4}-\sqrt{x}+\sqrt{x}=2+\sqrt{x}\\ \sqrt{2x+4}=2+\sqrt{x}$

Squaring both sides of the equation:

$(\sqrt{2x+4})^{2}=(2+\sqrt{x})^{2}$

Simplifying on the left side, and applying on the right side the formula:

$(a+b)^{2}=a^{2}+2ab+b^{2}; a=2, b=\sqrt{x}$

$2x+4=(2)^{2}+2(2)(\sqrt{x})+(\sqrt{x})^{2}\\ 2x+4=4+4\sqrt{x}+x$

Isolating the term with √x on the right side of the equation: Subtracting 4 and x from both sides of the equation:

$2x+4-4-x=4+4\sqrt{x}+x-4-x\\ x=4\sqrt{x}$

Squaring both sides of the equation:

$(x)^{2}=(4\sqrt{x})^{2}\\ x^{2}=(4)^{2}(\sqrt{x})^{2}\\ x^{2}=16 x$

This is a quadratic equation. Equaling to zero: Subtract 16x from both sides of the equation:

$x^{2}-16x=16x-16x\\ x^{2}-16x=0$

Factoring: Common factor x:

x (x-16)=0

Two solutions:

1) x=0

2) x-16=0

Solving for x: Adding 16 both sides of the equation:

x-16+16=0+16

x=16

Let's prove the solutions in the orignal equation:

1) x=0:

$\sqrt{2x+4}-\sqrt{x}=2\\ \sqrt{2(0)+4}-\sqrt{0}=2\\ \sqrt{0+4}-0=2\\ \sqrt{4}=2\\ 2=2$

x=0 is a solution

2) x=16

$\sqrt{2x+4}-\sqrt{x}=2\\ \sqrt{2(16)+4}-\sqrt{16}=2\\ \sqrt{32+4}-4=2\\ \sqrt{36}-4=2\\ 6-4=2\\ 2=2$

x=16 is a solution

Then the solutions are x=0 and x=16

5 0

3 years ago

Is 3 times 2/7 less than 3

kenny6666 [7]

Answer:

Yes

Step-by-step explanation:

You can set up your proportion as $\frac{3}{1}$ * $\frac{2}{7}$ you then multiply across to get $\frac{6}{7}$ . Since this number is less than 1, it's definitely less than 3.

3 0

3 years ago