(2x2 − x) + (x2 + 3x − 1)

Which values from the set 5,7,11,13 make the inequality w 4 < 8 true

Butoxors [25]

Answer:

C

Step-by-step explanation:trust me

3 0

3 years ago

Fuel for the reasearch vessels will be stored in a cylindrical tank with a radius of 10 meters and a height of 5 meters. Using a

Lemur [1.5K]

The volume of the tank is 1570 cubic meters

<h3>How to determine the volume</h3>

The formula for determining the volume of a cylinder is expressed as;

Volume = πr²h

Where;

radius is 10 meters
height is 5 meters
pi = 3. 14

Now, let's substitute into the formula;

Volume = 3. 14 × 10² × 5

Volume = 3. 14 × 100 × 5

Multiply through

Volume = 1570 cubic meters

Thus, the volume of the tank is 1570 cubic meters

Learn more about volume here:

brainly.com/question/1972490

#SPJ1

6 0

2 years ago

The local bike shop sells a bike and accessories package for $276. If the bike is worth 5 times more than the accessories, how m

aksik [14]

$1380 is the price of the bike, because $276 multiplied by 5 is $1380

3 0

3 years ago

(5/8 x - 10) - (1/8 x - 12)

nikklg [1K]

Answer: 16x-25 over 4(4x-5)(2x-3)

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

April worked 1 1/2 times as long on her math project as did Carl. Debbie worked 1 1/4 times as long as Sonia. Richard worked 1 3

vlada-n [284]

Answer:

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = $5\frac{1}{4}\ hrs$

$5\frac{1}{4}\ hrs$ can be Rewritten as $\frac{21}{4}\ hrs$

Number of Hours Carl worked on Math project = $\frac{21}{4}\ hrs$

Number of Hours Sonia worked on Math project = $6\frac{1}{2}\ hrs$

$6\frac{1}{2}\ hrs$ can be rewritten as $\frac{13}{2}\ hrs$

Number of Hours Sonia worked on Math project = $\frac{13}{2}\ hrs$

Number of Hours Tony worked on Math project = $5\frac{2}{3}\ hrs$

$5\frac{2}{3}\ hrs$ can be rewritten as $\frac{17}{3}\ hrs.$

Number of Hours Tony worked on Math project = $\frac{17}{3}\ hrs.$

Now Given:

April worked $1\frac{1}{2}$ times as long on her math project as did Carl.

$1\frac{1}{2}$ can be Rewritten as $\frac{3}{2}$

Number of Hours April worked on math project = $\frac{3}{2}$ $\times$ Number of Hours Carl worked on Math project

Number of Hours April worked on math project = $\frac{3}{2}\times \frac{21}{4} = \frac{63}{8}\ hrs \ \ Or \ \ 7\frac{7}{8} \ hrs$

Also Given:

Debbie worked $1\frac{1}{4}$ times as long as Sonia.

$1\frac{1}{4}$ can be Rewritten as $\frac{5}{4}$ .

Number of Hours Debbie worked on math project = $\frac{5}{4}$ $\times$ Number of Hours Sonia worked on Math project

Number of Hours Debbie worked on math project = $\frac{5}{4}\times \frac{13}{2}= \frac{65}{8}\ hrs \ \ Or \ \ 8\frac{1}{8}\ hrs$

Also Given:

Richard worked $1\frac{3}{8}$ times as long as tony.

$1\frac{3}{8}$ can be Rewritten as $\frac{11}{8}$

Number of Hours Richard worked on math project = $\frac{11}{8}$ $\times$ Number of Hours Tony worked on Math project

Number of Hours Debbie worked on math project = $\frac{11}{8}\times \frac{17}{3}= \frac{187}{24}\ hrs \ \ Or \ \ 7\frac{19}{24}\ hrs$

Hence We will match each student with number of hours she worked.

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

5 0

3 years ago

Read 2 more answers