My number has 8 tens .the digit in the ones place is greater than the digit in the teens place

I need help on both of them pls help me...

pav-90 [236]

.8 where cooked by the rooms combined 2) 25% pick blue and red

5 0

2 years ago

Riley and Erik have earned a total of 135 tokens to buy items in the school store. The ratio of the number of tokens that Riley

lisabon 2012 [21]

Answer:

<em>Riley has 72 tokens</em>

Step-by-step explanation:

<u>System of Equations </u>

We have two conditions for the tokens Riley and Erik have earned. Let's call x and y to the number of tokens of Riley and Erik respectively. The first condition states that

$x+y=135$

Solving for y

$y=135-x$

The second condition is that the ratio of the number of tokens that Riley had to the number of tokens that Erik has is 8 to 7. It's written as

$\displaystyle \frac{x}{y}=\frac{8}{7}$

Or equivalently

$7x=8y$

Replacing y from the first equation

$7x=8(135-x)$

Operating

$7x=1080-8x$

Simplifying

$15x=1080$

$\boxed{x=72}$

Riley has 72 tokens

3 0

3 years ago

Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the

Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees was $x+\frac{1}{4} x=\frac{5}{4} x$ , and for the next three years we have that

Start End

Second year $\frac{5}{4}x$ -------------- $\frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x$

Third year $(\frac{5}{4} )^{2}x$ ------------- $(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x$

Fourth year $(\frac{5}{4})^{3}x$ -------------- $(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.$