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Elanso [62]
3 years ago
13

PLSS HELP 25 POINTS AND BRAINLIEST

Mathematics
2 answers:
photoshop1234 [79]3 years ago
3 0

Answer:

136

Step-by-step explanation:

7*5=35

35+35=70

1/2*6*4=12

12+12=24

6*7=42

70+42+24=136

sorry if it is wrong.

bija089 [108]3 years ago
3 0

Answer:

\Large \boxed{\sf 136 \ m^2}

Step-by-step explanation:

S.A = Area of 2 triangles + Area of 3 rectangles

\displaystyle ((4 \times 6 \times \frac{1}{2}) \times 2)+((7 \times 5) \times 2 + (6 \times 7))=136

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Are the answers correct or am I missing some?
AlekseyPX
Well,

Emily received $40.00 and then withdrew $40.00.  The final amount would be zero.

Jacoby climbed 782 feet to get to his campsite, and then descended 782 feet to get back to his car.  His final change is zero.

The Eagles mad two points, but then the Bulldogs evened it out with another two points.  The difference between the two scores would be the same.

Marcus ends up going down more than he goes up, so this is not a correct option.

The Ravens scored two points, but at the end the Raiders scored an additional 5 points, which set both teams to the same score.

Since there are an equal number of protons and electrons, and the protons have the same (but opposite) amount of charge as the electrons, the charges cancel each other out, leaving the atom with a neutral overall charge (0).
8 0
3 years ago
If x is divided by 5 the remainder is 4. If why is divided by 5 the remainder is 1. What is the remainder when x+y is divided by
Naddik [55]

Answer:

0

Step-by-step explanation:

We are given the following:

\frac{x}{5}=q_1+\frac{4}{5}      (equ. 1)

\frac{y}{5}=q_2+\frac{1}{5}      (equ. 2)

We are asked:

\frac{x+y}{5}=q_3+\frac{r}{5}  (equ. 3) , what is r?

The q_i's represent the quotients you get.

r is the remainder of dividing x+y by 5.

We know that r is a number in {0,1,2,3,4}.

x=5q_1+4 (I got this by multiplying both sides of equ 1. by 5.)

y=5q_2+1 (I got this by multiplying both sides of equ 2. by 5.)

Let's add these equations together:

x+y=(5q_1+5q_2)+(4+1)

Factoring the 5 out for the q_i's part and simplify 4+1 gives:

x+y=5(q_1+q_2)+5

So 5 can't be the remainder of dividing something by 5 but see that we can factor this right hand expression more as:

x+y=5(q_1+q_2+1)

So q_3=q_1+q_2+1 while there is no remainder (the remainder is 0).

Let's do an example if you are not convinced at this point that the remainder will be 0.

So choose x=9 since 9/5 gives a remainder of 4.

And choose y=16 since 16/5 gives a remainder of 1.

x+y=9+16=25 and 25/5 gives a remainder of 0.

8 0
3 years ago
Diego is solving the equation x^2-12x = 21
uysha [10]

Answer:

The solutions to the quadratic equations will be:

x=\sqrt{57}+6,\:x=-\sqrt{57}+6

Step-by-step explanation:

Given the expression

x^2-12x\:=\:21

Let us solve the equation by completing the square

x^2-12x\:=\:21

Add (-6)² to both sides

x^2-12x+\left(-6\right)^2=21+\left(-6\right)^2

simplify

x^2-12x+\left(-6\right)^2=57

Apply perfect square formula: (a-b)² = a²-2ab+b²

i.e.

x^2-12x+\left(-6\right)^2=\left(x-6\right)^2

so the expression becomes

\left(x-6\right)^2=57

\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}

solve

x-6=\sqrt{57}

add 6 to both sides

x-6+6=\sqrt{57}+6

Simplify

x=\sqrt{57}+6

also solving

x-6=-\sqrt{57}

add 6 to both sides

x-6+6=-\sqrt{57}+6

Simplify

x=-\sqrt{57}+6

Therefore, the solutions to the quadratic equation will be:

x=\sqrt{57}+6,\:x=-\sqrt{57}+6

5 0
3 years ago
Vocabulary Which of the following describes the median of a data set?
Allushta [10]

Answer:

C is the answer

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Please help me in this questions....​
Ivahew [28]

Part (i)

I'm going to use the notation T(n) instead of T_n

To find the first term, we plug in n = 1

T(n) = 2 - 3n

T(1) = 2 - 3(1)

T(1) = -1

The first term is -1

Repeat for n = 2 to find the second term

T(n) = 2 - 3n

T(2) = 2 - 3(2)

T(2) = -4

The second term is -4

<h3>Answers: -1, -4</h3>

==============================================

Part (ii)

Plug in T(n) = -61 and solve for n

T(n) = 2 - 3n

-61 = 2 - 3n

-61-2 = -3n

-63 = -3n

-3n = -63

n = -63/(-3)

n = 21

Note that plugging in n = 21 leads to T(21) = -61, similar to how we computed the items back in part (i).

<h3>Answer:  21st term</h3>

===============================================

Part (iii)

We're given that T(n) = 2 - 3n

Let's compute T(2n). We do so by replacing every copy of n with 2n like so

T(n) = 2 - 3n

T(2n) = 2 - 3(2n)

T(2n) = 2 - 6n

Now subtract T(2n) from T(n)

T(n) - T(2n) = (2-3n) - (2-6n)

T(n) - T(2n) = 2-3n - 2+6n

T(n) - T(2n) = 3n

Then set this equal to 24 and solve for n

T(n) - T(2n) = 24

3n = 24

n = 24/3

n = 8

This means 2n = 2*8 = 16. So subtracting T(8) - T(16) will get us 24.

<h3>Answer: 8</h3>
4 0
3 years ago
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