Simplified version would be 2/5
Answer:
- no real solutions
- 2 complex solutions
Step-by-step explanation:
The equation can be rearranged to vertex form:
x^2 -4x = -5 . . . . . . . . . subtract 4x
x^2 -4x +4 = -5 +4 . . . . add 4
(x -2)^2 = -1 . . . . . . . . . show the left side as a square
x -2 = ±√-1 = ±i . . . . . . take the square root; the right side is imaginary
x = 2 ± i . . . . . . . . . . . . . add 2. These are the complex solutions.
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<em>Comment on the question</em>
Every 2nd degree polynomial equation has two solutions. They may be real, complex, or (real and) identical. That is, there may be 0, 1, or 2 real solutions. This equation has 0 real solutions, because they are both complex.
<u>Answer</u>
1
<u>Explanation</u>
The general equation of a wave is ;
y = a sin(kX+Ф)
Where a represent the amplitude, 360/k represent the period of the wave and Ф represent the phase angle.
∴ In the equation y = 1 sin 2x,
Amplitude = 1
Answer:
<h3>cosθ = c/√1+c²</h3>
Step-by-step explanation:
Given cot θ = c and 0 < θ < π/2
In trigonometry identity:
cotθ = 1/tanθ = c
1/tanθ = c
cross multiply
tanθ = 1/c
According to SOH, CAH, TOA:
Tanθ = opposite/adjacent = 1/c
cosθ = adjacent/hypotenuse
To get the hypotenuse, we will use the pythagoras theorem:
hyp² = opp²+adj²
hyp² = 1²+c²
hyp = √1+c²
Find cosθ in terms of c
cosθ = c/√1+c²
Hence the formula for cos θ in terms of c is cosθ = c/√1+c²
Answer:
78.5°
Step-by-step explanation:
We solve for the above question, using the formula for the Trigonometric function of Cosine
cos θ = Adjacent/Hypotenuse
Adjacent = The distance between the house and the base of the ladder = 4 feet
Hypotenuse = Length of the Ladder = 20 feet
Hence,
cos θ = 4/20
θ = arc cos(4/20)
θ = 78.463040967°
Approximately = 78.5°
Therefore, the angle that the ladder makes with the ground is 78.5°
