the sum of the geometric sequence is [3/2+3/8+3/32+3/128+3/512] =(1/512)*[256*3+64*3+16*3+4*3] =(3/512)*[256+64+16+4] =(3/512)*[340] =(1020/512) =255/128---------> 1.9922
the answer is 1.9922
another way to calculate it <span>is through the following formula </span>∑=ao*[(1-r<span>^n)/(1-r)] </span> where ao---------> is the first term r----------> is the common ratio<span> between terms n----------> </span><span>is the number of terms ao=1.5 r=1/4-----> 0.25 n=5 so </span>∑=1.5*[(1-0.25^5)/(1-0.25)]-------------> 1.99
