21−=2(2−)=2cos(−1)+2 sin(−1)
−1+2=−1(2)=−1(cos2+sin2)=cos2+ sin2
Is the above the correct way to write 21− and −1+2 in the form +? I wasn't sure if I could change Euler's formula to =cos()+sin(), where is a constant.
complex-numbers
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edited Mar 6 '17 at 4:38
Richard Ambler
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asked Mar 6 '17 at 3:34
14wml
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1 Answer
1
No. It is not true that =cos()+sin(). Notice that
1=1≠cos()+sin(),
for example consider this at =0.
As a hint for figuring this out, notice that
+=ln(+)
then recall your rules for logarithms to get this to the form (+)ln().
2004436the answer is2004436
Answer:
x = 7
Step-by-step explanation:
7x - 12 = 9x - 26
7x - 12 = 9x - 26
+12 +12
7x = 9x - 14
7x = 9x - 14
-9x -9x
-2x = -14
-2x = -14
___. ___
-2 -2
x = 7
The distance from any point P (x,y) on the parabola to the focus = the distance of this point from the directrix.
distance between P to focus:-
= sqrt ( x - 2)^2 + (y - 5))^2
distance from the point to directrix = ( 9 - y)
so sqrt( x - 2)^2 + (y-5)^2 = 9 -y
(x - 2)^2+ (y - 5)^2 = (9-y)^2
x^2 -4x + 4 + y^2 - 10y + 25 = 81 - 18y + y^2
x^2 - 4x + 4 +25 - 81 = -18y + 10y
-8y = x^2 - 4x -52
y = (-1/8)^2 + 1/2 x + 6 1/2 is the required equation
False because 90 is grater right
